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If using numbers 0 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Wiki User
∙ 6y ago
In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel.
There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
Wiki User
∙ 6y ago
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How many combinations can be made from 1234567890?
If repeats are allowed than an infinite number of combinations is possible.
How many odd 3- digit positive integers can be written using the digits 1 2 4 7 and 8?
If repeats are permitted: 2 x 5 x 5 = 50 different odd numbers If repeats are not permitted: 2 x 4 x 3 = 24 different odd numbers
What are all 5 digit combinations with 1-9?
from 1-9 have 9 numbers so that we have 9*9*9*9*9=59049 Consider the case of 5-digit number combinations, where each is some digit from 1 through 9. There are 9 different digits you can pick for the first number. Assuming you can have repeats, there are 9 you can pick for the second, 9 you can pick for the third, and 9 you can pick for the fourth and 9 you can pick for the fifth.
Is 1.131331333133331...a rational number?
no, rational numbers have a pattern that repeats, this number doesn't.
How many 5 numbers combinations can you make from the numbers 1 to 49 and you can use multiple combinations but still use each number only once?
If the 1, 2, 3, 4 and 5 each appear in the numbers (no repeats, no eliminations-- so numbers like 11133 are not valid) then there are 120 combinations. If you can use any of the 5 any number of times up to a max of 5 times, (any possible way of making a 5 digit number using only 1, 2, 3, 4 and 5, so that 33455 for example is valid) then the number of combinations is 3125. The 3125 combinations include the 120 combinations above. This is a permutation of 5 objects, that can be thought of as an arrangement or a rearrangement of the five numbers. The number of permutations of this 5 numbers is equal to 5!. 5! = 5 x 4 x 3 x 2 x 1 = 120 ways. Or you can use the graphing calculator to compute 5!, such as: Press 5, MATH, with the right arrow go to PRB, press 4 (for !), ENTER.
If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
How many different ways can I place 4 numbers?
Without repeats, 24. With repeats, 256.
How many combinations can be made from 1234567890?
If repeats are allowed than an infinite number of combinations is possible.
How many 3 digit combinations can be formed using 0 5 7 8?
Assuming you are using combinations in the colloquial way (which is the mathematical "permutations" where order of selection does matter) to create a 3 digit number that does not start with 0, ie creating a number that is between 100 and 999 inclusive then: If repeats are not allowed there are 3 × 3 × 2 = 18 possible numbers If repeats are allowed, then there are 3 × 4 × 4 = 48 possible numbers. If you are using combinations in the mathematical sense where order of selection does not matter and are creating groups of 3 digits, then: If repeats are not allowed there are 4 possible groups If repeats are allowed there are 20 possible groups.
How is a rational number that repeats different from a irratrional number that repeats?
Irrational numbers can not be repeating decimals. Any number that is a repeating decimal is rational.
How do you generate a list of five digit combinations of only the numbers 1 2 3 4 and 5 with out repeats?
you could make a probability tree if you could be bothered
How many 6 number combinations can you make with numbers 1-50. No 1 number repeats?
The number of combinations is 50C6 = 50*49*48*47*46*45/(6*5*4*3*2*1) = 15,890,700
How many different 2 digit numbers can be formed from the digits 2 6 7 and 8?
Without repeats there are 4 × 3 = 12 possible 2 digit numbers. With repeats there are 4 × 4 = 16 possible 2 digit numbers.
How many 8 number combinations are their using numbers 0 -9?
there are 10 numbers that you can choose from 0-9 you are choosing 8 at a time, meaning no repeats so the answer is "10 choose 8" or 10!/(8!*(8-2)!)
How many 6 number combinations can made from 50 numbers 1-50?
We are not told anything about repeats so I will assume you can repeat a digit. For example, you can have 111111 The first digits has 50 choices so does the second and the third..etc so we have 50^6 combinations.
How many 3 digit even numbers can be formed by using numbers 01234?
Assuming leading zeros are not permitted, then: If repeats are not allowed there are 30 possible numbers. If repeats are allowed there are 60 possible numbers.
How many odd 3- digit positive integers can be written using the digits 1 2 4 7 and 8?
If repeats are permitted: 2 x 5 x 5 = 50 different odd numbers If repeats are not permitted: 2 x 4 x 3 = 24 different odd numbers
