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Q: How many combinations of 8 numbers are there in 56 numbers?

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8C3 = 56 of them

28, or 56 counting reversals

There are 8*7/(2*1) = 28 combinations.

two

There is just 1 combination of 8 numbers taken 8 at a time.

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8C3 = 56 of them

56 combinations. :)

28, or 56 counting reversals

There are 125970 combinations and I am not stupid enough to try and list them!

There are 8*7/(2*1) = 28 combinations.

8C4 = 70

two

There is just 1 combination of 8 numbers taken 8 at a time.

Assuming that the eight numbers are all different and that none of them are zero, the number of combinations is 8C3 = 8!/(3!*5!) where n! = 1*2*3*...*n the number is 8*7*6 / (3*2*1) = 56

64

You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.

nCr = n!/((n-r)!r!) → 49C8 = 49!/((49-8)!8!) = 49!/(41!8!) = 450,978,066 combinations.

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