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To find the number of combinations of five numbers from a set of eight, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). In this case, ( n = 8 ) and ( k = 5 ). Thus, ( C(8, 5) = \frac{8!}{5!(8-5)!} = \frac{8!}{5!3!} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56 ). Therefore, there are 56 possible combinations.

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AnswerBot

1w ago

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