There are 90 of them.
90 of them.
There are 5 of them.
no it is a prime number (prime means its multiples are only 1 and itself composite numbers can have multiples of many other things)
Well, honey, the digit 3 appears in every odd number that ends in 3, 13, 23, 33, and so on up to 39. So, in the first 40 odd numbers, the digit 3 appears 4 times. Math doesn't have to be a drag, darling!
There are 90 of them.
17, 37, 47, 67, 97
90 of them.
There are 5 of them.
Oh, what a lovely question! If we're looking for 2-digit numbers where the one's digit is greater than the ten's digit, we simply need to think about the possibilities. There are 36 such numbers, ranging from 12 to 98. Just imagine all the happy little numbers waiting to be discovered!
no it is a prime number (prime means its multiples are only 1 and itself composite numbers can have multiples of many other things)
Well, honey, the digit 3 appears in every odd number that ends in 3, 13, 23, 33, and so on up to 39. So, in the first 40 odd numbers, the digit 3 appears 4 times. Math doesn't have to be a drag, darling!
When the units digit equals the tens digit then the sum of the digits of a 2 digit number is double the units digit. In each tens range above 50, numbers below this critical point meet the requirement, numbers above this critical point have a sum LESS than double the units digit. The applicable numbers are 51-54 (4), 61-65 (5), 71-76 (6), 81-87 (7) and 91-98 (8). Then there are 4 + 5 + 6 + 7 + 8 = 30 qualifying numbers.
The number of composite numbers is infinite.
Only one positive prime number has a 5 in the ones digit. That prime number is 5. All other numbers with a 5 in the ones digit are composite because they will be divisible by 5.
There are infinitely many composite numbers with infinitely many factors.
The prime numbers with a units digit of 1 in the range 1 - 121 are :- 11, 31, 41, 61, 71 and 101.......making 6 primes in total.