There are 5 of them.
Without repetition, 300. Of these 48 will have a 2 in the units place.
That looks like it should be the same as 10 times (the number of times the digit 1 occursin the units place in the numbers from 10 to 100), which would work out to 90 .
90 of them.
There are four of them.
There are 5 of them.
Without repetition, 300. Of these 48 will have a 2 in the units place.
17, 37, 47, 67, 97
That looks like it should be the same as 10 times (the number of times the digit 1 occursin the units place in the numbers from 10 to 100), which would work out to 90 .
90 of them.
There are four of them.
Oh, what a lovely question! If we're looking for 2-digit numbers where the one's digit is greater than the ten's digit, we simply need to think about the possibilities. There are 36 such numbers, ranging from 12 to 98. Just imagine all the happy little numbers waiting to be discovered!
How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?
there are no 3 digit tis two digit! :) * * * * * 90 of them.
Assume that the pages are numbered 1-145 in order and we don't have any other page numbering system.In every ten pages the digit 5 will appear in the units column once,e.g. 5, 15, 25, 35, 45 etc.That makes 15 fives.In the 50's the digit 5 will also appear in the tens columne.g. 50,51,52,53,54,55,56,57,58,59That makes another 10 fives.Don't worry about page 55, remember we counted the unit's digit 5 first then the ten's digit 5.The book is too short to have digit 5 in the hundreds column.So the digit 5 appears 25 times in the numbering of a 145-page book. == Answer== From 1 to 145, we have 9 one-digit numbers and 100 two-digit numbers and 46 three-digit numbersIn one-digit numbers we have only one chance to have 5.In two-digit numbers we can have 5 in the units place, in the tens place or the both.If we have 5 in the units place, then we can fill up the tens place by the numbers from 1 to 9. So, we get 9 chances.If we have 5 in the hundreds place, then we can fill up the units place by the numbers from 0 to 9. So, we get 10 chances.In three digit numbers, we can’t have 5 in hundreds place and tens place because we have 145 pages in all. So, we can have 5 in units-place only.The hundreds place cannot be filled with any other number except 1.So, we can fill the tens place by the numbers from 0 to 4 only. So, we get 5 chances.In total, 25 times we come across 5. Source: www.icoachmath.com
To determine how many times the digit 7 goes into 87, we need to divide 87 by 7. Performing the division, we find that 7 goes into 87 12 times with a remainder of 3. Therefore, the digit 7 goes into 87 twelve times.
90 of them.