64 of them
A 41 inch cube is 41X41X41 inches. 413=68921 cubic inches. A 41 inch cube can be cut into 68921 one-inch cubes.
A cube made from 8 smaller cubes would have a greater volume than a long row of cubes if the row consists of fewer than 8 cubes. The volume of a cube is calculated as the side length cubed, and since 8 cubes can be arranged to form a larger cube, their combined volume will exceed that of a straight line of cubes. If the row also consists of 8 cubes and is arranged in a straight line, their volumes would be equal, but the cube would occupy a smaller space due to its three-dimensional shape.
Each cube has 8 vertices. Therefore, for 6 cubes, you would multiply the number of vertices per cube by the number of cubes: 8 vertices/cube × 6 cubes = 48 vertices. So, there are 48 vertices on 6 cubes.
To calculate the number of small cubes that can fit inside the largest cube, we need to find the volume of each cube. The formula for volume is side length cubed. So, the volume of the small cube is 1mm x 1mm x 1mm = 1mm³, and the volume of the largest cube is 4mm x 4mm x 4mm = 64mm³. Therefore, it would take 64 small cubes to fill the largest cube.
4 of them can.
512
A 41 inch cube is 41X41X41 inches. 413=68921 cubic inches. A 41 inch cube can be cut into 68921 one-inch cubes.
You would be adding volumes together; whatever configuration you put them would be irrelevant then. Assuming these are all 1" cubes, you would have first a long row of 8 (1"x1"x8" total) or a cube made of cubes (2"x2"x2" total) and they both come to 8 cubic inches.
216 are.
A cube made from 8 smaller cubes would have a greater volume than a long row of cubes if the row consists of fewer than 8 cubes. The volume of a cube is calculated as the side length cubed, and since 8 cubes can be arranged to form a larger cube, their combined volume will exceed that of a straight line of cubes. If the row also consists of 8 cubes and is arranged in a straight line, their volumes would be equal, but the cube would occupy a smaller space due to its three-dimensional shape.
Each cube has 8 vertices. Therefore, for 6 cubes, you would multiply the number of vertices per cube by the number of cubes: 8 vertices/cube × 6 cubes = 48 vertices. So, there are 48 vertices on 6 cubes.
The entire outer layer is painted so an 8x8x8 block inside isn't painted. Zero. All cubes are painted on at least one side and the 10x10x10 cube is painted on all sides. It's a 10x10x10 cube meaning there are 1000 cubelets. Ones on the inside too. So 8x8x8 = 512.
To calculate the number of small cubes that can fit inside the largest cube, we need to find the volume of each cube. The formula for volume is side length cubed. So, the volume of the small cube is 1mm x 1mm x 1mm = 1mm³, and the volume of the largest cube is 4mm x 4mm x 4mm = 64mm³. Therefore, it would take 64 small cubes to fill the largest cube.
4 of them can.
125 of them.
Assuming that the cubes are 1x1x1, there will be one thousand cubes in the larger cube.
A 1-foot cube has dimensions of 12 inches on each side. To find out how many 1-inch cubes fit into it, calculate the volume of the 1-foot cube, which is (12 \times 12 \times 12 = 1,728) cubic inches. Since each 1-inch cube occupies 1 cubic inch, a total of 1,728 one-inch cubes can fit into a 1-foot cube.