A cube has 8 vertices.
There are 64 such cubes.
Eight half inch cubes would fill a one inch cube.
The sample space is the 6 cubes.
you would need 8 cubes each of 1" to make a larger cube with 2" dimensions
There is a 9x9x9 and a 11x11x11 cube but no physical 10x10x10 cubes as of yet.
The entire outer layer is painted so an 8x8x8 block inside isn't painted. Zero. All cubes are painted on at least one side and the 10x10x10 cube is painted on all sides. It's a 10x10x10 cube meaning there are 1000 cubelets. Ones on the inside too. So 8x8x8 = 512.
cubes without paint: 83 = 512. cubes with paint: 103 - 83 = 1,000 - 512 = 488. there's another explanation on this site
103=10x10x10=1000
per face we have 10*10 = 100 Total = 6*100 = 600
there is fifty four cubes in a rub ix cube.
Edges . . .Each cube . . . 12Four cubes. . . 48Vertices . . .Each cube . . . 8Four cubes . . 32
6
There are 12 inches in 1 foot, so there would be (12x12x12 =) 1728 cubes in a solid 1-foot cube. To hollow it out, we remove a cube of 10x10x10 from the middle (leaving just the cubes on the outside), so the answer is (1728 - 10x10x10 = 1728 - 1000 =) 728 cubes. The other way to approach this is to consider the sides - a cube has 6 faces, each with (12x12 =) 144 cubes in it, so the answer seems like it should be (12x12x6 =) 864. This doesn't take into account the edges of the cube (which overlap between sides). There are 12 edges to the cube, each with 12 cubes in them, so we need to subtract these from the total, giving (864 - 12x12 = 864 - 144 =) 720. This is still not quite right, as we have now counted the corner cubes 3 times (as 3 faces meet at each corner), and then discounted them 3 times (as 3 edges meet at each corner), so the corner cubes are not currently accounted for. There are 8 corners, so 8 more cubes, so the true answer is (720 + 8 =) 728, which is the same answer as we got from the first method. The answer (checked by two different methods) is therefore 728.
20 cubes
A cube has 8 vertices.
1000