An 18-gon, or 18-sided polygon, has a total of 1800 degrees. This is calculated using the formula for the sum of the interior angles of a polygon, which is ((n - 2) \times 180) degrees, where (n) is the number of sides. For an 18-gon, it would be ((18 - 2) \times 180 = 16 \times 180 = 2880) degrees. Each interior angle of a regular 18-gon would therefore be 100 degrees.
(18-2)*180 = 2880 degrees
583 Degrees are in a 20-Gon
(n-2)180 degrees 180(18)= 1440 degrees 1440/18=80 degrees
20 degrees
3,960°
(18-2)*180 = 2880 degrees
583 Degrees are in a 20-Gon
(18-2)*180 = 2880 degrees
(n-2)180 degrees 180(18)= 1440 degrees 1440/18=80 degrees
it is normally all obtuse. * * * * * The sum of the interior angles of an n-gon is (n-2)*180 degrees. Since n = 18, the sum is 16*180 degrees. So each angle is 16*180/18 = 160 degrees.
20 degrees
3,960°
104
14400
360/18 = 20 degrees
There are 18 sides
Well, honey, an exterior angle of a polygon can be found by dividing 360 degrees by the number of sides. So for a 20-gon, each exterior angle would be 18 degrees. It's as simple as that, darling.