Q: How many diagonals are there in a polygon of 11 sides?

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An 11 sided polygon has 44 diagonals.

There are 44 diagonals in an 11-sided polygon. heres how to find the amount of diagonals: S=amount of sides 1/2 S(S-3)

number of diagonals in an n-sided polygon is n(n-1)/2 - n If the polygon has 12 sides, number of diagonals is 12(12-1)/2 -12 = (12)(11)/2 -12 = 132/2 - 12 = 66-12 = 54

Defining a diagonal as any two vertices that are not connected by an edge (non-adjacent) of the polygon, you can determine the amount of diagonals using the following formulas = sides in polygon(s*(s-3))/2So,(3*(3-3))/2 = 0(4*(4-3))/2 = 2(5*(5-3))/2 = 5(6*(6-3))/2 = 9(7*(7-3))/2 = 14(8*(8-3))/2 = 20(9*(9-3))/2 = 27(10*(10-3))/2 = 35(11*(11-3))/2 = 44So, the polygon would have to have somewhere between 10 and 11 sides. Since a polygon can not have fractional amount of sides, no polygon exists that has 42 diagonals.

11 sides The diagonal of a polygon is a line segment that joins two non adjacent vertices. So for a n-sided polygon, each vertex can be joined to n-3 other sides. So there ought to be n x (n-3) diagonals for a n-sided polygon; however, each diagonal is counted twice, once by the vertex at each end. So the number of diagonals is: diagonals = n (n-3) / 2 So for 44 diagonals: 44 = n (n-3) / 2 88 = n2 - 3n n2 - 3n - 88 = 0 (n - 11)(n + 8) = 0 n = 11 or -8 Since the number of sides can't be negative, the number of sides is 11, a hendecagon (or undecagon)

Related questions

You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.

11

An 11 sided polygon has 44 diagonals.

There are 44 diagonals in an 11-sided polygon. heres how to find the amount of diagonals: S=amount of sides 1/2 S(S-3)

It is an undecagon which has 11 sides Check: 0.5*(112-33) = 44 diagonals

An 11 sided polygon has 44 diagonals

11 sides

number of diagonals in an n-sided polygon is n(n-1)/2 - n If the polygon has 12 sides, number of diagonals is 12(12-1)/2 -12 = (12)(11)/2 -12 = 132/2 - 12 = 66-12 = 54

Defining a diagonal as any two vertices that are not connected by an edge (non-adjacent) of the polygon, you can determine the amount of diagonals using the following formulas = sides in polygon(s*(s-3))/2So,(3*(3-3))/2 = 0(4*(4-3))/2 = 2(5*(5-3))/2 = 5(6*(6-3))/2 = 9(7*(7-3))/2 = 14(8*(8-3))/2 = 20(9*(9-3))/2 = 27(10*(10-3))/2 = 35(11*(11-3))/2 = 44So, the polygon would have to have somewhere between 10 and 11 sides. Since a polygon can not have fractional amount of sides, no polygon exists that has 42 diagonals.

11 sides The diagonal of a polygon is a line segment that joins two non adjacent vertices. So for a n-sided polygon, each vertex can be joined to n-3 other sides. So there ought to be n x (n-3) diagonals for a n-sided polygon; however, each diagonal is counted twice, once by the vertex at each end. So the number of diagonals is: diagonals = n (n-3) / 2 So for 44 diagonals: 44 = n (n-3) / 2 88 = n2 - 3n n2 - 3n - 88 = 0 (n - 11)(n + 8) = 0 n = 11 or -8 Since the number of sides can't be negative, the number of sides is 11, a hendecagon (or undecagon)

A polygon with 11 sides is an undecagon

An undecagon is an 11 sided polygon