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How many diagonals does an 11-sided polygon have?
An 11 sided polygon has 44 diagonals.
How many diagonals are there in an 11-sided figure?
There are 44 diagonals in an 11-sided polygon. heres how to find the amount of diagonals: S=amount of sides 1/2 S(S-3)
How many diagonals would a 12-sided n-sided figure have?
number of diagonals in an n-sided polygon is n(n-1)/2 - n If the polygon has 12 sides, number of diagonals is 12(12-1)/2 -12 = (12)(11)/2 -12 = 132/2 - 12 = 66-12 = 54
How many sides would you find in a polygon which has 42 diagonals?
Defining a diagonal as any two vertices that are not connected by an edge (non-adjacent) of the polygon, you can determine the amount of diagonals using the following formulas = sides in polygon(s*(s-3))/2So,(3*(3-3))/2 = 0(4*(4-3))/2 = 2(5*(5-3))/2 = 5(6*(6-3))/2 = 9(7*(7-3))/2 = 14(8*(8-3))/2 = 20(9*(9-3))/2 = 27(10*(10-3))/2 = 35(11*(11-3))/2 = 44So, the polygon would have to have somewhere between 10 and 11 sides. Since a polygon can not have fractional amount of sides, no polygon exists that has 42 diagonals.
What is the number of sides of polygons which has 44diagonals?
11 sides The diagonal of a polygon is a line segment that joins two non adjacent vertices. So for a n-sided polygon, each vertex can be joined to n-3 other sides. So there ought to be n x (n-3) diagonals for a n-sided polygon; however, each diagonal is counted twice, once by the vertex at each end. So the number of diagonals is: diagonals = n (n-3) / 2 So for 44 diagonals: 44 = n (n-3) / 2 88 = n2 - 3n n2 - 3n - 88 = 0 (n - 11)(n + 8) = 0 n = 11 or -8 Since the number of sides can't be negative, the number of sides is 11, a hendecagon (or undecagon)
