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Defining a diagonal as any two vertices that are not connected by an edge (non-adjacent) of the polygon, you can determine the amount of diagonals using the following formula
s = sides in polygon
(s*(s-3))/2
So,
(3*(3-3))/2 = 0
(4*(4-3))/2 = 2
(5*(5-3))/2 = 5
(6*(6-3))/2 = 9
(7*(7-3))/2 = 14
(8*(8-3))/2 = 20
(9*(9-3))/2 = 27
(10*(10-3))/2 = 35
(11*(11-3))/2 = 44
So, the polygon would have to have somewhere between 10 and 11 sides. Since a polygon can not have fractional amount of sides, no polygon exists that has 42 diagonals.
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WHAT IS THE ANSWER TOD12N(N-3) GIVES THE NUMBER OF DIAGONALS d FOR A POLYGON WITH N SIDES.. use THIS EQUATION TO FIND THE NUMBER OF DIAGONALS FOR POLYGON THAT HAS 13 SIDES .SOLVE?
65
How can you find the number of diagonals in a polygon?
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon
What is the formula to find diagonals in polygon?
0.5*(n2-3n) where n is equal to the number of sides of the polygon
What rule can be used to find number of diagonals that can be drawn from one vertex of regular polygon?
You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.
How many diagonals are there in an 11-sided figure?
There are 44 diagonals in an 11-sided polygon. heres how to find the amount of diagonals: S=amount of sides 1/2 S(S-3)
How yo find the formula on how to solve the number of diagonals in a polygon?
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
WHAT IS THE ANSWER TOD12N(N-3) GIVES THE NUMBER OF DIAGONALS d FOR A POLYGON WITH N SIDES.. use THIS EQUATION TO FIND THE NUMBER OF DIAGONALS FOR POLYGON THAT HAS 13 SIDES .SOLVE?
65
How can you find the number of diagonals in a polygon?
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon
What is the formula to find diagonals in polygon?
0.5*(n2-3n) where n is equal to the number of sides of the polygon
How many diagonals does a 11 sided polygon have?
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
How do you find the number of diagonals in a polygon?
Use the formula of: 0.5*(n2-3n) whereby n is the number of sides of the polygon
How do you find the number of sides of a polygon given the number of diagonals?
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
What rule can be used to find number of diagonals that can be drawn from one vertex of regular polygon?
You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.
Where d is the number of diagonals of a polygon with n sides find d if equals 20?
1/2*(n2-3n) = number of diagonals 1/2*(202-60) = 170 diagonals
How many diagonals are there in an 11-sided figure?
There are 44 diagonals in an 11-sided polygon. heres how to find the amount of diagonals: S=amount of sides 1/2 S(S-3)
How do you find the diagonals in a pentagon?
Use the formula: 0.5*(n2-3n) whereas 'n' is the number of sides of the polygon So: 0.5*(25-15) = 5 diagonals
A polygon has 14 diagonals how many sides does it have?
To determine the number of sides in a polygon with 14 diagonals, we can use the formula for the number of diagonals in a polygon: D = n(n-3)/2, where n is the number of sides. By setting D = 14 and solving for n, we get n(n-3)/2 = 14. Simplifying this equation, we find that n^2 - 3n - 28 = 0. Factoring this quadratic equation, we get (n-7)(n+4) = 0. Therefore, the polygon has either 7 or -4 sides. Since the number of sides cannot be negative, the polygon must have 7 sides.
