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Defining a diagonal as any two vertices that are not connected by an edge (non-adjacent) of the polygon, you can determine the amount of diagonals using the following formula
s = sides in polygon
(s*(s-3))/2
So,
(3*(3-3))/2 = 0
(4*(4-3))/2 = 2
(5*(5-3))/2 = 5
(6*(6-3))/2 = 9
(7*(7-3))/2 = 14
(8*(8-3))/2 = 20
(9*(9-3))/2 = 27
(10*(10-3))/2 = 35
(11*(11-3))/2 = 44
So, the polygon would have to have somewhere between 10 and 11 sides. Since a polygon can not have fractional amount of sides, no polygon exists that has 42 diagonals.
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WHAT IS THE ANSWER TOD12N(N-3) GIVES THE NUMBER OF DIAGONALS d FOR A POLYGON WITH N SIDES.. use THIS EQUATION TO FIND THE NUMBER OF DIAGONALS FOR POLYGON THAT HAS 13 SIDES .SOLVE?
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How can you find the number of diagonals in a polygon?
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon
What is the formula to find diagonals in polygon?
0.5*(n2-3n) where n is equal to the number of sides of the polygon
What rule can be used to find number of diagonals that can be drawn from one vertex of regular polygon?
You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.
How many diagonals are there in an 11-sided figure?
There are 44 diagonals in an 11-sided polygon. heres how to find the amount of diagonals: S=amount of sides 1/2 S(S-3)
