The number of diagonals in an n-sided polygon is given by
nC2 - n (where n is the number of sides of the polygon)
or in the expanded form:
factorial (n) _______________________ {factorial (2) * factorial (n-2)}
substituting (n = 6) for a hexagon we get the number of diagonals as 9.
Similarly, substituting (n=5) for a pentagon we get the number of diagonals as 5.
Chat with our AI personalities
No. The only rigid polygon is a triangle. Any other needs diagonals - which break up the polygon into triangles.
there is 7 hexagons in the design
It has 2 diagonals
It has 9 diagonals
Some concave hexagons can. For an extremely crude figure, but the best that this browser will allow, see below (the full stops are only for positioning the diagonals):____________\.................\..\.................\../................//___________/