An n sided polygon has n*(n-3)/2 diagonals.
A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
1/2*36*(36-3) = 594 diagonals.
100*(100-3)/2 = 4850
There are 44 diagonals in an 11-sided polygon. heres how to find the amount of diagonals: S=amount of sides 1/2 S(S-3)
100 sided polygon has = n(n-3)/2 diagonals = 100(100-3)/2 = 4850 diagonals
A 4-sided polygon has 2 diagonals. A 5-sided polygon, 5. 6-sided, 9. By induction, an n-sided polygon has 'n*(n-3)/2' diagonals. "n" is how many sides a shape has. so, (7)*(7-3)/2 now we have, 7*4/2 so, 28/2 = 14 Therefore, a 7-sided polygon would have 14 diagonals.
For an n-sided polygon, the number of diagonals is 1+2+3+....+(n-4)+2(n-3). For a nine-sided polygon, there are 1+2+3+4+5+2(6)=27 diagonals.
An n sided polygon has n*(n-3)/2 diagonals.
A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
50*(50 - 3)/2 = 1175 diagonals.
1/2*36*(36-3) = 594 diagonals.
n(n-3)/2
The formula for finding the amount of diagonals in a polygon is n(n-3)/2. So 14(14-3)/2 = 77 Diagonals
The formula used to find the number of diagonals in a polygon is n(n-3)/2. 30 x 27/2 = 810/2 = 405 diagonals.
56*(56-3)/2 which is 1484