Q: How many different 5-letter arrangements can be formed from the letters in the name tyler if each letter is used only once in each arrangement?

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There are 172 different arrangements.

There are 6! = 720 different arrangements.

Answer: 7P4 = 840 arrangementsNumber of letters in the word ENGLISH : 7Number of letters to take: 4Number of arrangements:= 7P4= 7!/(7-4)!= 5040/6= 840

In the word "function" you have 8 letters. 6 different letters and 2 equal letters.The number of different arrangements that are possible to get are:6!∙8C2 = 720∙(28) = 20 160 different arrangements.

There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.

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120

from itertools import permutationsfrom string import joinarrangements = [ ]for p in permutations ( 'ugccsir', 6 ) :arrangement = join ( p, '' )if 'ui' in arrangement :continueif not arrangement in arrangements :arrangements . append ( arrangement )print len ( arrangements )The above Python code gives a result of 2,220.

There are 172 different arrangements.

There are 5*4*3 = 60 arrangements.

64 different arrangements are possible.

There are 6! = 720 different arrangements.

There are (1*5*4)*(3*2*1) = 120 arrangements.

There are 7!/(2!*2!) = 1260 arrangements.

6! = 6x5x4x3x2x1 = 720 arrangements

There are 4 letters in IOWA, all non repeating. Arrangements are 4! or 24.

Answer: 7P4 = 840 arrangementsNumber of letters in the word ENGLISH : 7Number of letters to take: 4Number of arrangements:= 7P4= 7!/(7-4)!= 5040/6= 840

40,320