There are 12 two letter arrangements of the letters in PARK.
Only 20.
Assuming you don't repeat letters:* 7 options for the first letter * 6 options for the second letter * 5 options for the third letter * 4 options for the fourth letter (Multiply all of the above together.)
If all the letters are unique in the set, there are 6 choices for the first letter, 5 for the second letter, 4 for the third letter, etc. This results in 6 X 5 X 4 X 3 X 2 = 720 arrangements. If some of the six letters are duplicated, there will be fewer distinct arrangements.
Infinitely many. You could, for example, cut out images of the 8 letters and paste then on the wall facing you. Each letter can take infinitely many positions on that wall so you have infinitely many arrangements.
the arrangements occur. if there are two of the same letter then 12 all different letters then 24 three letters the same then 5 four letters the same then 1
There are 5!/2! = 60 arrangements.
5*4=20
There are 12 two letter arrangements of the letters in PARK.
i believe it is 120
Only 20.
Algorithm is the only nine letter word.
The number of different three letter arrangements that can be done from theletters in the word "mathematics"is; 11P3 =11!/(11-3)! =990
Assuming you don't repeat letters:* 7 options for the first letter * 6 options for the second letter * 5 options for the third letter * 4 options for the fourth letter (Multiply all of the above together.)
The number of arrangements of the letters PARTY, if the first letter must be an A is the same as the number of arrangements of the letters PRTY, and that is 4 factorial, or 24.
120
If all the letters are unique in the set, there are 6 choices for the first letter, 5 for the second letter, 4 for the third letter, etc. This results in 6 X 5 X 4 X 3 X 2 = 720 arrangements. If some of the six letters are duplicated, there will be fewer distinct arrangements.