To determine the number of different 5-card hands that can be dealt from a deck of 13 cards, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ), where ( n ) is the total number of cards, and ( k ) is the number of cards to choose. In this case, ( n = 13 ) and ( k = 5 ). Calculating this gives:
[ C(13, 5) = \frac{13!}{5!(13-5)!} = \frac{13!}{5! \times 8!} = \frac{13 \times 12 \times 11 \times 10 \times 9}{5 \times 4 \times 3 \times 2 \times 1} = 1287. ]
Thus, there are 1,287 different 5-card hands that can be dealt from a deck of 13 cards.
If only one card is dealt randomly from a deck of cards, the probability is 1/52.
You can draw C(52,13) = 52! /13! 39! = 635 013559 600 different 13-card hands from a deck of 52 cards.
Player 1 is holding 5 cards, Player 2 is dealt five cards from the same deck. Probabilities are: 1.card of player two matches one of the five cards of player 1: 15/47 2.card...:12/46 3.card...:9/45 4.card...:6/44 5.card...:3/43 ->Probability of 2 players having the same cards is all probabilities multiplied: 81/511313 or 0.000158416! Hope there is no mistake. Greets Tobi
The odds of being dealt exactly a full house are 694 to 1 against, which equates to a probability of 0.00144. The probability of all 5 card hands can be found, along with explanations of how to derive the probabilities, can be found at http://www.microcentrics.com/fivecard.aspx.
There are 52 cards of which 26 (a half) are black. So he probability that the first card is black is 26/52= 1/2
Assuming the 52 cards are all different, the first card can be any of the 52, the second card can be any of the remaining 51, and the third card can be any of the remaining 50, so there are 52x51x50 different three card hands possible.
If the cards are all different then there are 13C7 = 1716 different hands.
It is 1 in 17. Here's why: There are 52 cards in a deck, 13 different value cards (A, 2, 3, etc.), and two cards are dealt. We're finding the odds of getting any pocket pair, not just one. This means that the first card dealt can be any value. The second card has to repeat the value of the first card. For example, the first card dealt is a 10, and now the second card has to be a 10. After the first 10 is dealt, there are 51 cards left in the deck, and 3 different 10's. Therefore, 3 over 51 simplifies to 1 over 17.
Poker is a card game that involves betting and the winner is determined by the ranks and combinations of the cards and the hidden cards. A Poker Challenge is trying to identify the Poker hands within the dealt cards.
In the card game "Hands and Feet," players are dealt two sets of cards - one for their "hands" and one for their "feet." The goal is to create melds of cards in runs or sets. Players can also pick up cards from the discard pile or draw from the deck. The game is played in teams of two, and the team with the most points at the end of the game wins.
You are dealt a 5-card hand from a deck of 52 cards. Let event F equal "all the cards in your hand are from the same suit" and let event S equal "the numbers of your cards form an uninterrupted sequence."Which of the following hands are contained in the event F
In Hold-em the first three cards is the "flop", the next card is the "turn" and the last card is the "river".
Indian Marriage is a type of Rummie game. Your goal is to have the most points after all the hands are played out. You are dealt 21 cards. After, everyone deals a card face down the highest card takes all the cards, and you start again left of the person who won that hand.
If only one card is dealt randomly from a deck of cards, the probability is 1/52.
There are 15,820,024,220 ways.
The minimum number of cards that must be dealt, from an arbitrarily shuffled deck of 52 cards, to guarantee that three cards are from some same suit is 9.The basis for 9 is that the first four cards could be from four different suits, the next four cards could be from four different suits, and the ninth card is guaranteed to match the suit of two of the previously dealt cards. The minimum number, without the guarantee, is 3, but the probability of that is only 0.052, or about 1 in 20.
You can draw C(52,13) = 52! /13! 39! = 635 013559 600 different 13-card hands from a deck of 52 cards.