about...
25
just take 5 numbers times 5 numbers
8
6, as long as they are all different
55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.
With 123 digits you can make 123 one-digit numbers.
6 2-digit numbers (13/15/35/53/51/31)
8
6, as long as they are all different
If you want 4-digit numbers, there are 24 of them.
55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.
With 123 digits you can make 123 one-digit numbers.
6 2-digit numbers (13/15/35/53/51/31)
12 numbers
120
how make the answer im don/now
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
Not sure what a "didget" is. It is possible to make 18 5-digit numbers.
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.