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How many different three member committees can be formed from a group of twenty-five people?

There are 2300 possible combinations.


How many 2-member committees can be formed from a group of 7 people?

-5


How many different committees can be selected from a group of 10 people if a committee must have between 2 and 4 people?

5 for 2, 3 for 3, 2 for 4.


How many two person committees can be chosen from a group of nine people?

72


How many committees of 7 can be formed from a group of 10 people?

There are: 10C7 = 120


How many 4-person committees are possible from a group of 9 people if there are no restrictions?

-5


How many different two person committees can be formed from a group of six people?

To determine the number of different two-person committees that can be formed from a group of six people, we use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ), where ( n ) is the total number of people and ( k ) is the number of people to choose. Here, ( n = 6 ) and ( k = 2 ). Thus, the number of combinations is ( C(6, 2) = \frac{6!}{2!(6-2)!} = \frac{6 \times 5}{2 \times 1} = 15 ). Therefore, 15 different two-person committees can be formed.


Could someone use the word a group of specialist and if use does it mean all the group member are of one specialty?

no it means a group of people that may have different specialties within the group


How many 4 person committees can be chosen from a group of 32?

The number of distinct, different 4-person committees that can be formedfrom a group of 32 people is(32!/28!) / (4!) = (32 x 31 x 30 x 29) / (4 x 3 x 2 x 1) = 35,960(but obviously, no more than four at a time.)


How many 3 member committed can you choose from a group of 18 students?

To determine how many 3-member committees can be formed from a group of 18 students, you can use the combination formula: (C(n, r) = \frac{n!}{r!(n-r)!}), where (n) is the total number of students and (r) is the number of members in the committee. In this case, (n = 18) and (r = 3). Thus, the calculation is (C(18, 3) = \frac{18!}{3!(18-3)!} = \frac{18 \times 17 \times 16}{3 \times 2 \times 1} = 816). Therefore, you can form 816 different 3-member committees from the group of 18 students.


How many people in a sextet?

Six


People who are paid by certain groups to talk to Congressional committees about their group's point of view on certain laws?

They are called `lobbyists`.