-5
72
5 for 2, 3 for 3, 2 for 4.
The number of distinct, different 4-person committees that can be formedfrom a group of 32 people is(32!/28!) / (4!) = (32 x 31 x 30 x 29) / (4 x 3 x 2 x 1) = 35,960(but obviously, no more than four at a time.)
no its not possible . because max. no of edges formed will be 36. and for this condition we need 45 edges. so this is not possible
8.7.6/3! = 56 Here is why this works. There are 8 choices for the fist member of the committee. Then we have 7 choices for the next and 6 for the last. HOWEVER, when picking a committee, the order does not matter. So for example if we pick Chuck, Judy and Melanie and we denote them as C, J and M respectively, then one committee is CJM but that is the same committee as CMJ and MCJ. In fact, there are 3! or 3x2x1=6 ways to arrange the 3 members so we must divide 8x7x6 by 6 and the result is 56 committees of 3 people picked from 8. Picking a committee is an example of a combination problem in math. If order mattered it would be a permutation.
There are: 10C7 = 120
There are 2300 possible combinations.
The committees of correspondence was a group of representatives from each of the thirteen colonies that was created to help the colonies keep in contact. from each meeting they would let the people of their colony know what was going on.
Eight. If you can't multiply by fives, then your either an idiot, or too young to be using the Internet.
They can't be split evenly into groups of six. Sixteen people can split into two groups of six, and there will be four people left over.
72
Do your homework. Quit cheating.
-5
The answer is 7C5 = 21.
(9 x 8 x 7 x 6)/(4 x 3 x 2 x 1) = 126committees.
The ones connected directly to the First Continental Congress (September 1774) and the Revolutionary War (April 1775) were formed in 1772 and 1773. Earlier committees had been formed in response to the Stamp Act in 1764.
1316