there can be only three combo's ------ head n tail,,,,,,,, tail n tail,,,,,,,,,,,,,, head n head
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If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
The number of possible combinations of three different words depends on the total number of words available. If you have ( n ) distinct words, the number of combinations of three words can be calculated using the combination formula ( C(n, 3) = \frac{n!}{3!(n-3)!} ). This formula gives you the total ways to choose 3 words from ( n ) without regard to the order of selection. For example, if you have 10 words, the number of combinations would be ( C(10, 3) = 120 ).
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
Starting with three different letters, six two-letter combinations can be made, if the order of the two letters is important. Only three combinations can be made if the order of the two letters is not important. Example: ABC AB AC BA BC CA CB - six variations But if (for your purposes) BA is the same as AB, Then there are only three: AB AC BC
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18 different combinations. When a coin is tossed twice there are four possible outcomes, (H,H), (H,T), (T,H) and (T,T) considering the order in which they appear (first or second). But if we are talking of combinations of the two individual events, then the order in which they come out is not considered. So for this case the number of combinations is three: (H,H), (H,T) and (T,T). For the case of tossing a die once there are six possible events. The number of different combinations when tossing a coin twice and a die once is: 3x6 = 18 different combinations.
Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.
Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.
Four of them.
There are 23 possible outcomes this is found by there being 2 possibilities ( head or tails) that is done three times, that is 2X2X2= 8 possible combinations for the outcome. This is if order matters, that is h h t is different to t h h
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
There are 2300 possible combinations.
The three possible combinations would be continental-continental, continental-oceanic, and oceanic-oceanic.
Eight of them.
There are eight (8).
If the gene for a trait has two alleles, one dominant (D) and one recessive (d) there are three possible combinations in the genotype: DD (homozygous dominant) Dd (heterozygous) dd (homozygous recessive)