there can be only three combo's ------ head n tail,,,,,,,, tail n tail,,,,,,,,,,,,,, head n head
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If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
Starting with three different letters, six two-letter combinations can be made, if the order of the two letters is important. Only three combinations can be made if the order of the two letters is not important. Example: ABC AB AC BA BC CA CB - six variations But if (for your purposes) BA is the same as AB, Then there are only three: AB AC BC
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.