48
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
Starting with three different letters, six two-letter combinations can be made, if the order of the two letters is important. Only three combinations can be made if the order of the two letters is not important. Example: ABC AB AC BA BC CA CB - six variations But if (for your purposes) BA is the same as AB, Then there are only three: AB AC BC
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
48
18 different combinations. When a coin is tossed twice there are four possible outcomes, (H,H), (H,T), (T,H) and (T,T) considering the order in which they appear (first or second). But if we are talking of combinations of the two individual events, then the order in which they come out is not considered. So for this case the number of combinations is three: (H,H), (H,T) and (T,T). For the case of tossing a die once there are six possible events. The number of different combinations when tossing a coin twice and a die once is: 3x6 = 18 different combinations.
Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.
Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.
Four of them.
There are 23 possible outcomes this is found by there being 2 possibilities ( head or tails) that is done three times, that is 2X2X2= 8 possible combinations for the outcome. This is if order matters, that is h h t is different to t h h
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
There are 2300 possible combinations.
The three possible combinations would be continental-continental, continental-oceanic, and oceanic-oceanic.
There are eight (8).
Eight of them.
6 different combinations can be made with 3 items