Eight of them.
9, you just have to multiply for problems like this
There are 23 = 8 possible outcomes.
There are 48 possible outcomes and I have no intention of listing them all. They are all of the form CCCD where C = H or T, and D takes the numeric values from 1 to 6.
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
There are three possibilities, Heads, Tails and stand on edge
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
It depends on the definition of an outcome. If you care about the order of the tosses, <br /> you get 2 possible outcomes per toss. Three tosses give you 2*2*2=8 possible outcomes. If you only care about the final number of heads and tails, there are 4 possible outcomes (3 heads, 2 heads and a tail, a head and two tails, or 3 tails).
three heads two head, one tails one heads, two tails three tails
Given that x is cross and o is head the possible outcomes would be: x-x-x o-x-x x-o-x x-x-o o-o-x o-x-o x-o-o o-o-o Thence there are 8 possible outcomes. Assumptions: 1) Each coin ends up head or tail (never on its side) 2) The coins are distinctinguishable (maybe a penny dime and quarter). If three identical perfectly balanced pennies are tossed at the same time there are 4 outcomes (all heads or all tails 1/8 of the time each and just one or just 2 heads 3/8 of the time each)