There are eight (8).
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9, you just have to multiply for problems like this
Given that x is cross and o is head the possible outcomes would be: x-x-x o-x-x x-o-x x-x-o o-o-x o-x-o x-o-o o-o-o Thence there are 8 possible outcomes. Assumptions: 1) Each coin ends up head or tail (never on its side) 2) The coins are distinctinguishable (maybe a penny dime and quarter). If three identical perfectly balanced pennies are tossed at the same time there are 4 outcomes (all heads or all tails 1/8 of the time each and just one or just 2 heads 3/8 of the time each)
three heads two head, one tails one heads, two tails three tails
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
C(8,3) = 56