0
Infinitely many.
Select any number L, greater than sqrt(24) units an let B = 24/L.
then the rectangle with sides measuring L and B will have an area of L*B = L*24/L = 24 square units.
Also, B ≤ sqrt(24) ≤ L so that value of L gives a different rectangle. And, since there are infinitely many possible values for L, there are infinitely many possible rectangles.
Still curious? Ask our experts.
Chat with our AI personalities
Blake
Rafa
ViviAdd your answer:
Earn +20 pts
How many different rectangles can you draw with an area of 12 cm2?
9
How many different rectangles with an area of 32 square units can you make?
To find the different rectangles with an area of 32 square units, we need to consider the factor pairs of 32. The pairs are (1, 32), (2, 16), (4, 8), and their reverses, giving us the dimensions of the rectangles: 1x32, 2x16, 4x8, and 8x4. However, since the order of dimensions does not create a new rectangle, we have four unique rectangles: 1x32, 2x16, and 4x8. Thus, there are three distinct rectangles with an area of 32 square units.
How many different rectangles can have an area of 24 square inches if their lengths and widths are whole numbers?
4
How many rectangles have the same area and perimeter of 18?
thare is only 1 differint rectangles
How many rectangles have the same area but different perimeters?
Infinitely many. Suppose the area of the rectangle is 100. We could create rectangles of different areas: 100x1 50x2 25x4 20x5 10x10 However, the side lengths need not be integers, which is why we can create infinitely many rectangles. Generally, if A is the area of the rectangle, and L, L/A are its dimensions, then the amount 2(L + (L/A)) can range from a given amount (min. occurs at L = sqrt(A), perimeter = 4sqrt(A)) to infinity.
