Q: How many different ten digit number can be formed using the digits zero until nine excluding numbers starting with zero?

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It is a count of all digits, excluding leading zeros before the decimal point.

Ten different digits can be used to make 10C4 = 10*9*8*7/(4*3*2*1) = 210 four-digit numbers. Either numbers starting with 0 are permitted or the 10 digits do not contain a 0.

24, of which 6 will begin with zero. Excluding these, gives 18.

89,999 different numbers i guess

There are only five distinct odd digits.

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There are 22680 numbers, excluding those with leading 0s.

Excluding numbers which begin with 0, there are 67,200 of them.

It is a count of all digits, excluding leading zeros before the decimal point.

By simply re-ordering the digits, you can get 500 6-digit numbers, excluding those starting with 0. There are thousands more that can be made using mathematical operations such as addition, subtraction, multiplication, division, exponentiation, factorials and so on.

Ten different digits can be used to make 10C4 = 10*9*8*7/(4*3*2*1) = 210 four-digit numbers. Either numbers starting with 0 are permitted or the 10 digits do not contain a 0.

24, of which 6 will begin with zero. Excluding these, gives 18.

24, if you permit numbers starting with 0, 18 otherwise.

89,999 different numbers i guess

There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.

There are only five distinct odd digits.

Different schemes have different id numbers of different lengths.

Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.