0
The answer is 7! = 5040 ways. Label the 7 people A through G. Person A can pick from 7 different available positions. Person B can now choose from 6 different positions. Person C can choose from 5 available positions. On down to person G has one choice, so this is 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5040. This type of multiplication is so common in statistics that it has a name - factorial function, and is abbreviated by the exclamation mark (n! = n x (n-1) x (n-2) x ... x 2 x 1)
Still curious? Ask our experts.
Chat with our AI personalities
Taiga
Ross
SteveAdd your answer:
Earn +20 pts
How many different ways can 6 people stand in line?
36
How many ways can 7 people stand in a line?
5040
How many different ways can 7 people stand in line for movie tickets?
There are 7 people who could stand first, with 6 people who could stand second for each of those first people, with 5 people who could stand third for each of those first two people, and so on, until with 1 person left who could stand seventh for each of the first six people. This gives 7 × 6 × 5 × ... × 1 = 5040 ways.
How many ways can 5 people stand in a strait line if Jessie is always third?
Not sure what a strait line is! Five people can stand in a straight line, with Jessie third in 24 ways if you ignore left-to-right and right-to-left "reflections".
If there were twenty one people in a line how many different combinations are there in the order of the line?
420
