The digit appears eleven time from 1 to 100.
900
There are 280.
100 to 900
there are 999 - 100 + 1 = 900 positive triple digit positive integers, between 100 and 999.(e.g. there are 102 - 100 + 1 = 3 triple digit integers between 100 and 102,namely 100, 101 and 102.)multiply that by 2 to take in consideration of the negative integers,you have 1800 triple digit integers.
There are 90 two-digit whole numbers between 1 and 100.
how does 100 meet the specification? 1 is in the hundreds digit and 0 is in the tens digit. 1 is not at least 0. this is a confusing question?!
The digit appears eleven time from 1 to 100.
900
There are 280.
9
100 to 900
there are 999 - 100 + 1 = 900 positive triple digit positive integers, between 100 and 999.(e.g. there are 102 - 100 + 1 = 3 triple digit integers between 100 and 102,namely 100, 101 and 102.)multiply that by 2 to take in consideration of the negative integers,you have 1800 triple digit integers.
100 times greater.
There are 5 of them.
The largest 3-digit number=999 the smallest 3-digit number=100 total number of 3 digit number=(999-100)+1 =899+1=900
10 times for the one's digit, 1-100 10 times for the ten's digit, 60-70 = 20 times