Since a tennis ball has a diameter that is greater than 2 inches, the answer is 0.
If the other dimensions (length and height) are left unchanged, doubling the width will double the volume.
the dimensions of the cylinder would be 2 times greater. We just had a test on this stuff and this was one of the questions.
None. Multiplying two dimensions gives area, not volume.
As long as the cubes are 1x1x1 then any box with an equivalent volume would hold the same number of cubes. The volume of the 3x4x10 box is 120. So a box with the dimensions 1x1x120 would work just as well as a box with the dimensions 12x10x1 or 2x5x12.
It is not possible to determine the number of tennis balls without knowing the volume of a single tennis ball. Once you know the volume of one tennis ball, you can calculate the number of balls needed to fill 55444 cubic feet.
241920 in^3 == typical minivan cargo volume (V) 17.576 in^3 == volume of a cube surrounding a tennis ball (v) 13764 == V/v = number of tennis ball sized cubes to fit into the cargo space of a minivan
Volume has three dimensions - width, height and depth.
How many balls are in one can? Three? If so, then calculate the volume of one ball and multiply by three. That's the volume occupied by the balls. The volume of a sphere is given by the formula V = 4(Pi)r3/3. Now calculate the volume of the cylinder. Assume that its height is three times the diameter of a ball (if there are three balls in the can). Remember that the diameter is twice the radius. Also, assume that the radius of the can is equal to the radius of one ball. The volume of a cylinder is given by the formula V = (Pi)r2h. Now subtract the volume of the balls from the volume of the can.
For a box, the dimensions the define a volume would be:Height, Width, and DepthFor a cylinder, the dimensions that define a volume would be:Height and Diameter
Volume always has three dimensions. Area always has two dimensions. Length always has one dimension. Location has no dimensions.
We have two boxes.The dimensions of the smaller box are 'L', 'W', and 'H'. (Length, Width, and Height)Its volume is V1 = (L x W x H).The dimensions of the larger box are 3L, 3W, and 3H.Its volume is V2 = (3L x 3W x 3H) = 27 x (L x W x H) = 27 x V1.V2/V1 = 27.We just demonstrated that volume is proportional to the cube of the linear dimensions. This is true for any solid.
I regret to inform you that I am unable to provide you with an answer to your question. However, I can tell you how you would go about finding the answer. The first step would be to find the volume of your can. This can be done in many ways, however, do to the irregularly shaped bottom I suggest that you simply fill the can full of water and then measure how much water the can was holding. Whatever number you get will be the can's volume in units cubed. Your second step is to find the volume of a tennis ball. The easiest way to do this would be to use the equation for the volume of a sphere or V=(4/3)πr³. Knowing that the radius of a tennis ball is 1.125 inches you simply plug that into the equation and get V≈5.964 inches cubed. Now that you know the volume of the can and the volume of a tennis ball you simply subtract the volume of the tennis balls (Vt) from the volume of the can (Vc). The equation would look like this. Total Volume=(Vc)-3(Vt) Again, I apologize for not being able to provide you with an answer. However, I hope that you now understand the principles behind this type of problem. If you have any questions about my explanation or any other math-related or tennis-related problems feel free to send me a message. Zilduli
Consider: a standard tennis ball is 65.41-68.58 millimeters in diameter, so (at the midpoint) ~0.157 liters volume. A random sphere packing is about 36% empty space, so the exclusive volume is ~0.246 liters per ball -- 4 balls per litter. Answer - 40 Balls
Look at the picture.
twice
Guesstimate: 170,000. this is based on a diameter of 6.7 cm. per ball, and dimensions of 9m times 2.25m times 2.5m for the bus. (The figure I came up with is 170,859 and I rounded it to 170,000.)