A set of half dollar quarter and dime is worth 50+25+10 = 85 cents. So, with an equal number of these coins the sum can only be a multiple of 85 cents. 15 dollars is not a multiple so cannot be so changed.
1 quarter (25¢) 3 dimes (55¢) 6 nickles (85¢) 15 pennies (100¢)
.82, .85, .88
6816 quarters would weigh about 85 pounds.
85 ft.
85 dimes = 85*10 cents = 85*10/25 quarters = 34 quarters.
4 quarters=10 dimes x quarters=85 dimes quarter=10/4 dimes x (10/4 dimes) = 85 dimes x= 85 dimes/(10/4 dimes) x=34 Answer: 34 quarters
3 quarters & 2 nickels
A set of half dollar quarter and dime is worth 50+25+10 = 85 cents. So, with an equal number of these coins the sum can only be a multiple of 85 cents. 15 dollars is not a multiple so cannot be so changed.
85
2 quarters, 3 dimes, 1 nickel, 3 pennies. I worked it out by knowing that 3 pennies would be needed for sure (to get from 85 to 88), but not 8 pennies, since there's no 80 cent coin. Then just started working it out with quarters, then seeing how many dimes, and then nickels would work out to the six remaining coins.
Two quarters, one dime, four nickels, five pennies
1 quarter (25¢) 3 dimes (55¢) 6 nickles (85¢) 15 pennies (100¢)
I don't think that this can be done using current US coins. In Canada, however, there are at least three combinations: -- 80 cents, 17 dimes, 2 quarters and a two-dollar coin -- 85 cents, 9 dimes, 5 quarters and a two-dollar coin -- 90 cents 1 dime, 8 quarters and a two dollar coin
85 deciliters equal 850cL
.82, .85, .88
85 millimeters is equal to 3.3464567 inches.