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How many distinct arrangements can be made with the letters in the word banana?

There are 6!/(3!*2!) = 60 arrangements.


How many distinct four letter arrangements can be found in theword FLUFFY?

360


How many distinct ordered arrangements can be made with the letters of mississippi?

There are 34650 distinct orders.There are 34650 distinct orders.There are 34650 distinct orders.There are 34650 distinct orders.


How many arrangements of the letters BOX are possible if you use each letter only once in each arrangement?

The word "BOX" consists of 3 distinct letters. The number of arrangements of these letters can be calculated using the factorial of the number of letters, which is 3! (3 factorial). Therefore, the total number of arrangements is 3! = 3 × 2 × 1 = 6. Thus, there are 6 possible arrangements of the letters in "BOX."


How many different arrangements can be made with the letters from the word GRAPHICS?

64 different arrangements are possible.


How many different arrangements are possible for the prime factors of 12?

12


How many arrangements are possible in the word loner?

5! = 5x4x3x2x1 = 120


How many distinct arrangements can be made with the letters in the word surprising?

Take note of the word "surprising":There are 10 letters total.There are 2 r's.There are 2 i'sThere are 2 s's.There are 10! total ways to arrange the letters. Since repetition is not allowed for the arrangements, we need to divide the total number of arrangements by 2!2!2! Therefore, you should get 10!/(2!2!2!) distinct arrangements


How many five-letter arrangements are possible from the five letters MAMMM?

Five


How many distinct three letter arrangements can be found from the letters in mathematics?

The number of different three letter arrangements that can be done from theletters in the word "mathematics"is; 11P3 =11!/(11-3)! =990


How many distinct arrangements can be made with the letters in the word BOXING?

The number of distinct arrangements of the letters of the word BOXING is the same as the number of permutations of 6 things taken 6 at a time. This is 6 factorial, which is 720. Since there are no duplicated letters in the word, there is no need to divide by any factor.


How many distinct arrangements can be made from the word college?

The word "college" has 7 letters, including 2 'l's and 2 'g's, which are repeated. To find the number of distinct arrangements, we use the formula for permutations of multiset: [ \frac{n!}{n_1! \cdot n_2!} ] where (n) is the total number of letters, and (n_1), (n_2) are the frequencies of the repeated letters. Here, (n = 7), (n_1 = 2) (for 'l'), and (n_2 = 2) (for 'g'): [ \text{Distinct arrangements} = \frac{7!}{2! \cdot 2!} = \frac{5040}{4} = 1260. ] Thus, there are 1,260 distinct arrangements of the letters in "college."