To find the number of distinguishable arrangements of the letters "aaabb," we use the formula for permutations of multiset:
[ \frac{n!}{n_1! \times n_2!} ]
where ( n ) is the total number of letters, ( n_1 ) is the number of indistinguishable letters of one type, and ( n_2 ) is the number of indistinguishable letters of another type. Here, ( n = 5 ) (total letters), ( n_1 = 3 ) (for 'a'), and ( n_2 = 2 ) (for 'b').
Calculating this gives:
[ \frac{5!}{3! \times 2!} = \frac{120}{6 \times 2} = \frac{120}{12} = 10 ]
Thus, there are 10 distinguishable ways to arrange the letters "aaabb."
three
7 factorial
There are 7 factorial, or 5,040 permutations of the letters of ALGEBRA. However, only 2,520 of them are distinguishable because of the duplicate A's.
25 times
12
There are 4 distinguishable letters in the word fish, so there is 4! or 24 different ways can you arrange the letters in the word fish.
cat
three
7 factorial
120?
There are 7 factorial, or 5,040 permutations of the letters of ALGEBRA. However, only 2,520 of them are distinguishable because of the duplicate A's.
40
The word mathematics has 11 letters; 2 are m, a, t. The number of distinguishable permutations is 11!/(2!2!2!) = 39916800/8 = 4989600.
25 times
24 ways.
10080
12