The DISTRIBUTIVE property is a property of multiplication over addition (OR subtraction) over some specified set of numbers. It states that, a*(b + c) = a*b + a*c for any elements a, b and c belonging to the set,
Multiplication has a distributive property OVER addition, and according to it: a*(b + c) = a*b + a*c for all elements of the appropriate set.
A=(L,I,V,E) B=(V,I,L,E) C=(L,I,V,E) AB and C are equal because they have the same elements and the same number of elements. F=(1,2,1,3,21,19) R=(abacus) R and F are equal because they are precisely the same. I HOPE ITS USEFUL !
The COMMUTATIVE property states that the order of the arguments of an operation does not matter. In symbolic terms, for elements a and b and for the operation ~, a ~ b = b ~ a The ASSOCIATIVE property states that the order in which the operation is carried out does not matter. Symbolically, for elements a, b and c, (a ~ b) ~ c = a ~ (b ~ c) and so, without ambiguity, either can be written as a ~ b ~ c. The DISTRIBUTIVE property is a property of two operations, for example, of multiplication over addition. It is not the property of a single operation. For operations ~ and # and elements a, b and c, symbolically, this means that a ~ (b # c) = a ~ b # a ~ c. The existence of an IDENTITY is a property of the set over which the operation ~ is defined; not a property of operation itself. Symbolically, if the identity exists, it is a unique element, denoted by i, such that a ~ i = a = i ~ a for all a in the set. For example, you can define addition on all positive integers which will have the commutative and associative properties but the identity (zero) and additive inverses (negative numbers) are undefined as far as the set is concerned. I have deliberately chosen ~ and # to represent the operations rather than addition or multiplication because there are circumstances in which these properties do not apply to multiplication (for example for matrices), and there are many other operations that they can apply to.
According the associative property of multiplication, given any three elements a, b and c belonging to a set, (ab)c = a(bc) and so without ambiguity either can be written as abc. By contrast, (a/b)/c is not equal to a/(b/c). The first is a/bc, the second is ac/b which is true only if c2 = 1 ie c = -1 or c = 1
If every element of B is contained in C, then B is a subset of C. If every element of B is contained in C and B is not the same as C, then B is a proper subset of C.The cardinal number of a set is the number of elements in the set.In this case, C has 8 elements, so B has at most 7 elements.
Q = {a,b,c}
The DISTRIBUTIVE property is a property of multiplication over addition (OR subtraction) over some specified set of numbers. It states that, a*(b + c) = a*b + a*c for any elements a, b and c belonging to the set,
Multiplication has a distributive property OVER addition, and according to it: a*(b + c) = a*b + a*c for all elements of the appropriate set.
Cardinality is simply the number of elements of a given set. You can use the cardinality of a set to determine which elements will go into the subset. Every element in the subset must come from the cardinality of the original set. For example, a set may contain {a,b,c,d} which makes the cardinality 4. You can choose any of those elements to form a subset. Examples of subsets may be {a,c} {a, b, c} etc.
There are 2 elements: ab is one and c is the other.
puts "0" set a 0 set b 1 set c 0 for {set i 1} {$i < 8} {incr i} { set a $b set b $c set c [expr $b + $a] puts $c } -------->by No Rule
If a set has six elements, for example {A, B, C, D, E, F}, then it may have the following subsets: - the set itself - 6 sets of five elements - 15 sets of four elements - 20 sets of three elements - 15 sets of two elements - 6 sets of one element - 1 set with no elements (the null set), for a total of 64 sets, which is 2^6, or 2 to the 6th power.
B. C, for example does not have structured classes.
c) formed elements
A=(L,I,V,E) B=(V,I,L,E) C=(L,I,V,E) AB and C are equal because they have the same elements and the same number of elements. F=(1,2,1,3,21,19) R=(abacus) R and F are equal because they are precisely the same. I HOPE ITS USEFUL !
NO. The set of numbers in Set B and the set of numbers in Set C CAN be the same, but are not necessarily so.For example if Set A were "All Prime Numbers", Set B were "All Even Numbers", and Set C were "All numbers that end in '2'", A union B would equal A union C since 2 is the only even prime number and 2 is the only prime number that ends in 2. However, Sets B and C are not the same set since 4 exists in Set B but not Set C, for example.However, we note in this example and in any other possible example that where Set B and Set C are different, one will be a subset of the other. In the example, Set C is a subset of Set B since all numbers that end in 2 are even numbers.