I believe you should be able to count those on your own.
The DISTRIBUTIVE property is a property of multiplication over addition (OR subtraction) over some specified set of numbers. It states that, a*(b + c) = a*b + a*c for any elements a, b and c belonging to the set,
Multiplication has a distributive property OVER addition, and according to it: a*(b + c) = a*b + a*c for all elements of the appropriate set.
A distinct pair refers to a unique combination of two elements or items where the order does not matter, and the elements are different from one another. For example, in the set {A, B, C}, the distinct pairs would be (A, B), (A, C), and (B, C). Each pair is considered distinct because it consists of different elements and is not repeated in any form.
A=(L,I,V,E) B=(V,I,L,E) C=(L,I,V,E) AB and C are equal because they have the same elements and the same number of elements. F=(1,2,1,3,21,19) R=(abacus) R and F are equal because they are precisely the same. I HOPE ITS USEFUL !
According the associative property of multiplication, given any three elements a, b and c belonging to a set, (ab)c = a(bc) and so without ambiguity either can be written as abc. By contrast, (a/b)/c is not equal to a/(b/c). The first is a/bc, the second is ac/b which is true only if c2 = 1 ie c = -1 or c = 1
If every element of B is contained in C, then B is a subset of C. If every element of B is contained in C and B is not the same as C, then B is a proper subset of C.The cardinal number of a set is the number of elements in the set.In this case, C has 8 elements, so B has at most 7 elements.
Q = {a,b,c}
The DISTRIBUTIVE property is a property of multiplication over addition (OR subtraction) over some specified set of numbers. It states that, a*(b + c) = a*b + a*c for any elements a, b and c belonging to the set,
Multiplication has a distributive property OVER addition, and according to it: a*(b + c) = a*b + a*c for all elements of the appropriate set.
Cardinality is simply the number of elements of a given set. You can use the cardinality of a set to determine which elements will go into the subset. Every element in the subset must come from the cardinality of the original set. For example, a set may contain {a,b,c,d} which makes the cardinality 4. You can choose any of those elements to form a subset. Examples of subsets may be {a,c} {a, b, c} etc.
There are 2 elements: ab is one and c is the other.
puts "0" set a 0 set b 1 set c 0 for {set i 1} {$i < 8} {incr i} { set a $b set b $c set c [expr $b + $a] puts $c } -------->by No Rule
A distinct pair refers to a unique combination of two elements or items where the order does not matter, and the elements are different from one another. For example, in the set {A, B, C}, the distinct pairs would be (A, B), (A, C), and (B, C). Each pair is considered distinct because it consists of different elements and is not repeated in any form.
B. C, for example does not have structured classes.
c) formed elements
A=(L,I,V,E) B=(V,I,L,E) C=(L,I,V,E) AB and C are equal because they have the same elements and the same number of elements. F=(1,2,1,3,21,19) R=(abacus) R and F are equal because they are precisely the same. I HOPE ITS USEFUL !
NO. The set of numbers in Set B and the set of numbers in Set C CAN be the same, but are not necessarily so.For example if Set A were "All Prime Numbers", Set B were "All Even Numbers", and Set C were "All numbers that end in '2'", A union B would equal A union C since 2 is the only even prime number and 2 is the only prime number that ends in 2. However, Sets B and C are not the same set since 4 exists in Set B but not Set C, for example.However, we note in this example and in any other possible example that where Set B and Set C are different, one will be a subset of the other. In the example, Set C is a subset of Set B since all numbers that end in 2 are even numbers.