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In order for the number to be even, the '2' must be the last digit. So we only need to
figure out how many ways there are to arrange the 1, 3, and 5 in the first 3 places.
The first place can be any one of 3 digits. For each of those ...
The second place can be either one of the 2 remaining digits.
And then the third place has to be the only digit that's left.
So there are (3 x 2) = 6 ways to arrange 1, 3, and 5 in the first 3 places.
That means only 6 even 4-digit numbers can be made from the digits 1, 2, 3, and 5.
And here they are:
1 3 5 2
1 5 3 2
3 1 5 2
3 5 1 2
5 1 3 2
5 3 1 2
What else can I help you with?
How many three digit even numbers with different digits can be written using the digits 0 1 and 2?
To form a three-digit even number with different digits using the digits 0, 1, and 2, the last digit must be even, which can only be 0 or 2. If the last digit is 0, the first digit can be either 1 or 2 (2 options), and the middle digit will take the remaining digit (1 option). This gives us 2 valid numbers: 120 and 210. If the last digit is 2, the first digit can only be 1 (since it cannot be 0), and the middle digit must be 0. This gives us 1 valid number: 102. In total, there are 3 different three-digit even numbers: 120, 210, and 102.
How many 3 digits even numbers can be formed if repetition of digits is possible?
To form a 3-digit even number, the last digit must be an even digit (0, 2, 4, 6, or 8), giving us 5 options for the last digit. The first digit can be any digit from 1 to 9 (9 options), and the second digit can be any digit from 0 to 9 (10 options). Therefore, the total number of 3-digit even numbers is calculated as (9 \times 10 \times 5 = 450).
What is the plural form for digits?
The plural form is digits; the singular form is digit.
How many different three digit numbers can you form using the digits 2 5 and 7?
6 possible 3 digit combonations
How many 4 digit numbers can you build if the number must be odd odd digits can be repeated and even digits cannot be repeated?
To form a 4-digit odd number, the last digit must be one of the odd digits (1, 3, 5, 7, 9), giving us 5 choices. For the first three digits, we can use odd digits freely (repeating allowed), giving us 5 choices for the first digit and 5 choices for the second digit. The third digit must be an even digit (0, 2, 4, 6, 8), but cannot repeat; therefore, we have 5 choices for the first digit and 4 choices for the second digit. Thus, the total number of valid 4-digit odd numbers is calculated as (5 \times 5 \times 5 \times 5 = 625).
How many even 3-digit numbers can be formed from the digits 1 2 3 and 5 if each digit can be used only once?
The final digit must be a 2 to form an even number. The first digit may be any of three remaining digits (1, 3, 5) while the second digit may be any of the two remaining digits. All together, that makes 3*2 = 6 distinct even numbers.
How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
How many 2 digit numbers digits can be written in accending form?
90 of them.
How many three digit even numbers with different digits can be written using the digits 0 1 and 2?
To form a three-digit even number with different digits using the digits 0, 1, and 2, the last digit must be even, which can only be 0 or 2. If the last digit is 0, the first digit can be either 1 or 2 (2 options), and the middle digit will take the remaining digit (1 option). This gives us 2 valid numbers: 120 and 210. If the last digit is 2, the first digit can only be 1 (since it cannot be 0), and the middle digit must be 0. This gives us 1 valid number: 102. In total, there are 3 different three-digit even numbers: 120, 210, and 102.
How many different numbers can you form if no digit is repeated?
The answer will depend on how many digits you have at your disposal. Working with the 10 digits, and barring leading zeros, there are 8,877,690 numbers.
How many 6 digit numbers can be formed form the digits 123456 if no digits can be repeated?
6*5*4*3*2*1=720 possible numbers
What is the plural form for digits?
The plural form is digits; the singular form is digit.
How many different three digit numbers can you form using the digits 2 5 and 7?
6 possible 3 digit combonations
How many six digit numbers can be formed using the digits 0123456789 Example equals 123456 or 098765?
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
What is the word form for each number and the value of the underlined digit?
Since there are no numbers and no underlined digits, there cannot be any answer!
How many different three digit numbers can you form using the digits 1 2 3 5 6 7 and 9 without repetition?
There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.
How many 5 digit numbers can be made using the digits 12679 if repetition isn't allowed?
To form a 5-digit number using the digits 1, 2, 6, 7, and 9 without repetition, we can use all five digits. The number of different arrangements of these 5 digits is calculated by finding the factorial of the number of digits, which is 5!. Therefore, the total number of 5-digit numbers that can be formed is 5! = 120.
