12
Two cubes have 12 faces, 24 edges, and 16 vertices.
no, all cubes have 6 faces. Just think about regular dice - they are cubes, and have the numbers 1 through 6. If a cube had 8 faces, the dice would have two empty faces!
Each cube has 6 faces, 12 edges and 8 vertices, so two [unconnected] cubes have 12 faces, 24 edges and 16 vertices (between them).
There will be 64 cubes total.The original 8 corners will have three red faces.The cubes that came from the original 12 edges excluding the original 4 corners will be 24 with two red faces (adjoining faces).There will also be leftover 24 cubes with one red face and 8 cubes with no red paint.8+24+24+8 = 64
12
Two cubes have 12 faces, 24 edges, and 16 vertices.
no, all cubes have 6 faces. Just think about regular dice - they are cubes, and have the numbers 1 through 6. If a cube had 8 faces, the dice would have two empty faces!
Well, each cube have six faces, multiplied by twenty-seven different cubes, equaling one hundred sixty-two (162) sides total.
Each cube has 6 faces, 12 edges and 8 vertices, so two [unconnected] cubes have 12 faces, 24 edges and 16 vertices (between them).
It depends on how they are connected, i.e. how many are connected to each other. If they are connected in a line, with just one connection between any two cubes, the rectangle formed still has 6 faces, four of them rectangular (10 of the original 36 cubic faces are hidden between cubes, leaving 26 showing). If the maximum number of faces are connected, with 4 of the cubes as a larger cube and the other two attached together to it, there would be 3 large irregular faces (sides and back), 2 large cubic faces (bottom and front) and 3 rectangular faces (half cubes) as seen from the top. The total would be 8.
All the little cubes except the one at the middle will have 1, 2 or 3 faces with paint on them, ie 26 of them will have some paint on them: 0 faces painted - 1 cube 1 face painted - 6 cubes (the centre ones of each side) 2 faces painted - 12 cubes (the ones in the centre of where two sides meet) 3 faces painted - 8 cubes (the ones in the corners).
There will be 64 cubes total.The original 8 corners will have three red faces.The cubes that came from the original 12 edges excluding the original 4 corners will be 24 with two red faces (adjoining faces).There will also be leftover 24 cubes with one red face and 8 cubes with no red paint.8+24+24+8 = 64
6/36
Draw a three dimensional cube, showing three faces. Divide each face into 6 x 6 =36 squares, representing the faces of the little cubes. Then by inspection it is obvious that no little cube can have more then three painted faces and they will be at the eight corners. Only the edge cubes (not counting the corners) can have two painted faces and there are 48 of then. Finally, only the inner cubes on the surfaces will have one painted face and there are 96 of them. The other 64 cubes are in the inner core and will have no painted surfaces. SO: 6 = 0 ; 5 = 0; 4 =0 ; 3 = 8 ; 2 = 48 ; 1 = 96 . uuuuuu.....
Coal cubes: 0. Sugar cubes: 0 Painted cubes: maybe some of them.
There are 12 squares on 2 cubes