6/36
assuming we are talking about standard dice here (six sided, numbered 1-6) then the probability of obtaining a result other than 12 when a single die is tossed is 100%. There is no way to roll a 12 after 1 toss of 1 die, therefore the chance of getting anything other than 12 is guaranteed
The probability is 90/216 = 5/12
A single fair die has the numbers 1 to 6, so when a single fair die is tossed the probability of obtaining a number different than 11 is: P(x diff than11) = 1.
The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5
50%
The probability is 6/36 = 1/6.
Coins do not have numbers, there is only the probability of heads or tails.
The probability that the die tossed will land on a number that is smaller than 5 is 4/6 or 2/3. Smaller than 5 is 1 - 4 and 6 is the sample space.
assuming we are talking about standard dice here (six sided, numbered 1-6) then the probability of obtaining a result other than 12 when a single die is tossed is 100%. There is no way to roll a 12 after 1 toss of 1 die, therefore the chance of getting anything other than 12 is guaranteed
The probability is 90/216 = 5/12
A single fair die has the numbers 1 to 6, so when a single fair die is tossed the probability of obtaining a number different than 11 is: P(x diff than11) = 1.
The probability is 1/16.
If the "number cube" you are referring to is what we normally call a die (one of a pair of dice), the chances of tossing an 8 are nothing since the cube has only 6 sides and is numbered 1 to 6. If a "number cube" is something else, perhaps someone else can answer the question.
1/6
1/4 if they are tossed only once.
The probability is 50-50.
The number of times a coin is tossed does not alter the probability of getting heads, which is 50% in every case, as long as the coin has not been rigged (i.e., a double-headed coin, a weighted coin) to alter the result.