To count to 31 in binary, you need enough flip-flops to represent the number 31 in binary form, which is 11111 (5 bits). Therefore, you would need 5 flip-flops to count from 0 to 31. Each flip-flop represents a single bit, and with 5 flip-flops, you can represent numbers from 0 to 31, inclusive.
8 digits just count the amount of numbers.
To write the numbers from 1 to 20, we need to count the digits used for each range. The numbers 1 to 9 use 1 digit each, totaling 9 digits. The numbers 10 to 20 use 2 digits each, totaling 22 digits (11 numbers). Therefore, the total number of digits required to write all the numbers from 1 to 20 is 9 + 22 = 31 digits.
3, sandwiched zeroes count
1 cause ( 2 ^ 0 ) = 1 index: 0 1 2 3 number: 1 2 4 8
It is a count of all digits, excluding leading zeros before the decimal point.
7 digits
4
4
(2^5) = 32 SO, 5 flipflops are required to produce a divide by 32 device
8 digits just count the amount of numbers.
To write the numbers from 1 to 20, we need to count the digits used for each range. The numbers 1 to 9 use 1 digit each, totaling 9 digits. The numbers 10 to 20 use 2 digits each, totaling 22 digits (11 numbers). Therefore, the total number of digits required to write all the numbers from 1 to 20 is 9 + 22 = 31 digits.
10,000....Count
it has 6 sig digits (405608) the 0.00 dont count
3, sandwiched zeroes count
1 cause ( 2 ^ 0 ) = 1 index: 0 1 2 3 number: 1 2 4 8
Three decade counter are required to count 999
It is a count of all digits, excluding leading zeros before the decimal point.