9999
999999999
To count significant figures, you count all the non-zero digits. You also count zeros which are between non-zero digits, as well as zeros which are after the decimal point, only if they appear to the right of non-zero digits.
21 bits.
Well, darling, the number 36.4375 has four decimal places. It's not rocket science, honey, just count those digits after the decimal point. So, in this case, you've got 4 decimal places to work with. Hope that clears things up for you!
Assuming you start from 0, you need at least 4 bits. 15 in binary: 15 = 8 + 4 + 2 + 1 = 1111₂
Count them: 643(10)=1010000011(2)
Binary numbers have only 2 digits, 0 and 1. Binary came from a need to represent information based in magnetics that only offer an "on" or "off" state. Decimal numbers have 10 digits, 0,1,2,3,4,5,6,7,8,9. Decimal numbers came about from humans having 10 fingers to count with. Once they reach 10, they start reusing fingers (digits). When humans count to 3, they count to their 3rd digit. Here's how to count to 3 in binary, which only has 2 digits: 01,10,11 Here's counting to 7 in decimal: 1,2,3,4,5,6,7 Here's counting to 7 in binary: 001,010,011,100,101,110,111 All of the mathematics done in decimal can be done in binary. No matter how fancy computers get, the bottom line is they have to store and manipulate information at a physical level, something physical must store all of that information. In computers, that physical storage is magnetic. All information is stored and manipulated at the lowest level as a combination of large binary values, large combinations of "on" and "off". Scientists are inventing new ways to store information in computers, so perhaps in time computer storage won't be limited to binary values.
9999
999999999
You can count to 999999, one short of a million.
1 cause ( 2 ^ 0 ) = 1 index: 0 1 2 3 number: 1 2 4 8
To count significant figures, you count all the non-zero digits. You also count zeros which are between non-zero digits, as well as zeros which are after the decimal point, only if they appear to the right of non-zero digits.
Count the digits to the right of the decimal and divide the digits number, without a decimal, by 1 with (2 + number of digits right of decimal) zeros. So. 490.4% = 4904/100 = 4.904
Just like decimal counting except you only have two digits (0 and 1) instead of 10 (0,1,2,3,4,5,6,7,8,9). But counting is the same. In decimal you count from 0 to 9, then you start over by putting a 1 in the "tens" place and a 0 in the "ones" place. Eg., 0,1,2,3,4,5,6,7,8,9,10,11,12, etc. Same with binary, except since you only have two digits, it goes 0,1, 10 (note I put a 1 in the "two's" place) 11, 100,101, 110,111, etc. In decimal you have the "ones, tens, hundreds, thousands" places, etc, and in binary you have the "Ones, twos, fours, eights" places, etc. So 100 has a 1 in the "fours" place and equals decimal count of 4. 101 has a 1 in the fours place, a 0 in the twos place, and a 1 in the ones place so it equals a decimal count of 5.
It is a count of all digits, excluding leading zeros before the decimal point.
Prime numbers are prime numbers - whether we count in the decimal, binary, hexadecimal or another base.