There are 5 letters: a c e f and h.
If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:
5*5*5*5 = 54 = 625.
There are 12 two letter arrangements of the letters in PARK.
There are 6! = 720 different arrangements.
None
There are 13 letters in "the world topic". This includes 2 ts and 2 os. Therefore there are 13!/[2!*2!] = 1556755200 different arrangements.
Infinitely many. You could, for example, cut out images of the 8 letters and paste then on the wall facing you. Each letter can take infinitely many positions on that wall so you have infinitely many arrangements.
Take note of the word "surprising":There are 10 letters total.There are 2 r's.There are 2 i'sThere are 2 s's.There are 10! total ways to arrange the letters. Since repetition is not allowed for the arrangements, we need to divide the total number of arrangements by 2!2!2! Therefore, you should get 10!/(2!2!2!) distinct arrangements
How many three-letter "words" can be made from 10 letters "FGHIJKLMNO" if repetition of letters are not allowed
There are 12 two letter arrangements of the letters in PARK.
6! = 6x5x4x3x2x1 = 720 arrangements
There are 6! = 720 different arrangements.
64 different arrangements are possible.
There are 4 letters in IOWA, all non repeating. Arrangements are 4! or 24.
There are 6!/(3!*2!) = 60 arrangements.
There are 5!/2! = 60 arrangements.
6! =720
5! 5 * 4 * 3 * 2 *1 = 120 arrangements you take the number of letters in the words and make it a factorial.
Answer: 7P4 = 840 arrangementsNumber of letters in the word ENGLISH = 7Number of letters to take= 4Number of arrangements:= 7P4= 7!/(7-4)!= 5040/6= 840