About 18,402 gallons.
Roughly 18,502 gallons
20000
That all depends on how deep the water has to be, which the question neglects to specify.
3.14 x28 x 28 /4 x 4 x 7.48gals/ cu ct = 18, 400 gallons
This pool can hold a maximum of about 18,420 gallons of water.
About 18,402 gallons.
Roughly 18,502 gallons
A 28-foot round pool filled with 4 feet of water would contain about 18,500 gallons.
20000
That all depends on how deep the water has to be, which the question neglects to specify.
What are your depths in the deep and shallow end and what shape is the pool? Rectangular, kidney, oval or irregular?
3.14 x28 x 28 /4 x 4 x 7.48gals/ cu ct = 18, 400 gallons
A child's wading pool would be filled with less than 28 gals.
To calculate the volume in gallons of a round pool, do the following calculation: diameter x diameter x depth x 5.9 Example: 28ft x 28ft x 4ft x 5.9 = 18,502.4 gallons
Assuming you mean the pool is 14 feet by 28 feet and has a shallow end of 4 feet and a deep end of 6 feet, then the total water volume would be approximately 14,700 gallons.
28 is the diameter of the pool and 4 is the height (depth). 1 cubic foot is approx. 7.48 gallons. A round swimming pool is a cylinder. So: pi x (28/2)2 x 4 = 2463 cubic feet, multiply by 7.48 = 18423.24 gallons