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To determine how many grams of NH₃ can be produced from 3.13 mol of N₂, we start with the balanced chemical equation: N₂ + 3H₂ → 2NH₃. From the equation, 1 mole of N₂ produces 2 moles of NH₃. Therefore, 3.13 moles of N₂ will produce 3.13 × 2 = 6.26 moles of NH₃. To convert moles of NH₃ to grams, we use its molar mass (approximately 17.03 g/mol): 6.26 mol × 17.03 g/mol = 106.36 grams of NH₃.
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How do you find 2.5 mol of sulfur in grams?
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How many grams of LiCl are required to make 2.0 of 0.65?
To calculate the grams of LiCl needed to make a 2.0 L solution at a concentration of 0.65 M, use the formula: [ \text{grams of solute} = \text{molarity} \times \text{volume (L)} \times \text{molar mass} ] The molar mass of LiCl is approximately 42.39 g/mol. Thus: [ \text{grams of LiCl} = 0.65 , \text{mol/L} \times 2.0 , \text{L} \times 42.39 , \text{g/mol} \approx 55.85 , \text{g} ] Therefore, approximately 55.85 grams of LiCl are required.
Consider the equation 2a plus b--a2b if you mix 1.0 mol of a and 1.0 mol of b how many moles of a2b can be produced?
Because it takes 2a to make 1mol of a2b, the ratio is 1mol a2b/2mol a. If you only have 1.0 mol of a to react, then 1mol a x (1mol a2b/2 mol a)= 0.5 mol of a2b Because it takes 1 mol of b to make 1 mole of a2b, the ratio is 1mol a2b/1mol b. So, 1.0 mol b x (1mol a2b/1mol b)= 1.0 mol of a2b. Since you run out of a to react with b, a is the limiting reagent meaning that you can only produce 0.5 mol of a2b even though you have an excess amount of b. So, only 0.5 mol of a2b can be produced.
How many grams of hydrogen are there in 150 g of ammonia?
To determine the amount of hydrogen in 150 g of ammonia (NH3), we first need to calculate the molar mass of ammonia. The molar mass of NH3 is approximately 17 g/mol (1 nitrogen atom with a molar mass of 14 g/mol and 3 hydrogen atoms with a molar mass of 1 g/mol each). Next, we find the molar ratio of hydrogen to ammonia, which is 3:1. Therefore, in 150 g of ammonia, there are approximately 33.53 grams of hydrogen (150 g / 17 g/mol * 3 mol H2 / 1 mol NH3).
How many grams are in 8.2 x 1022 molecules f N2l6?
To find the mass in grams of 8.2 x 10^22 molecules of N2l6, we first need to determine the molar mass of N2l6. The molar mass is calculated by adding the atomic masses of nitrogen (N) and iodine (l) in the formula. N has an atomic mass of approximately 14 g/mol and I has about 127 g/mol; thus, N2l6 has a molar mass of (2 * 14) + (6 * 127) = 868 g/mol. Next, we convert the number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol): 8.2 x 10^22 molecules * (1 mol / 6.022 x 10^23 molecules) ≈ 0.136 moles. Finally, we multiply the number of moles by the molar mass: 0.136 moles * 868 g/mol ≈ 118.5 grams. Therefore, there are approximately 118.5 grams of N2l6 in 8.2 x 10^22 molecules.
How many grams of CO2 are produced in 2.09 mol of HCl?
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How many grams of alcl3 are produced from with 8.0 moles of al2o3. 6cl2 plus 2al2o3 equals 3o2 plus 4alcl3 equals?
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
How many moles of aluminum are produced from 33 grams of aluminum?
To determine how many moles of aluminum are produced from 33 grams, divide the given mass by the molar mass of aluminum, which is approximately 26.98 g/mol. So, 33 g / 26.98 g/mol ≈ 1.22 moles of aluminum are produced.
How many grams of NH 3 can be produced from 3.91 mol of N 2 and excess H 2?
110 g ammonia are produced.
How many grams of NH3 can be produced from 2.63 mol of N2 and excess H2?
89,6 g ammonia are obtained.
How many grams of NH3 can be produced from 4.33 mol of N2 and excess H2. Express your answer numerically in grams.?
4.33 mol of N2 will produce twice as many moles of NH3 since the balanced chemical equation is N2 + 3H2 -> 2NH3. Therefore, 4.33 mol of N2 will produce 8.66 mol of NH3. To convert this to grams, use the molar mass of NH3 (17.03 g/mol) to find that 8.66 mol is equal to 147.43 grams of NH3.
How many grams of mercury are produced when 16 grams of HgO are heated?
The molar mass of Hg is 200.59 g/mol and of O is 16.00 g/mol. HgO consists of 1 Hg and 1 O atom, so the molar mass of HgO is 200.59 + 16.00 = 216.59 g/mol. To find the mass of mercury produced, we calculate the molar mass ratio of Hg to HgO: (200.59 g/mol Hg) / (216.59 g/mol HgO) = 0.926. When 16 grams of HgO are heated, the mass of mercury produced would be 16 g * 0.926 ≈ 14.82 grams.
How many grams of NH3 can be produced from 2.22 mol of N2 and excess H2.?
To determine the mass of NH3 produced from 2.22 mol of N2, we use the balanced equation for the synthesis of ammonia: N2 + 3H2 → 2NH3. From the equation, 1 mole of N2 produces 2 moles of NH3. Therefore, 2.22 mol of N2 will yield 2 × 2.22 = 4.44 mol of NH3. The molar mass of NH3 is approximately 17.03 g/mol, so the mass produced is 4.44 mol × 17.03 g/mol = 75.7 grams of NH3.
How many grams of co2 are in 2l mol of the compound?
92.4 grams
How many grams in 4.23 m mol of HBr?
The answer is 0,3422 grams.
How many grams of MgO are produced when 40 grams of 02 react with Mg?
Using the balanced chemical equation: 2Mg + O2 -> 2MgO, we can see that 1 mol of O2 reacts with 2 moles of Mg to produce 2 moles of MgO. Calculate the moles of O2: 40g O2 / 32g/mol = 1.25 mol O2 From the equation, 1.25 mol O2 will produce 2.5 mol of MgO. Calculate the grams of MgO produced: 2.5 mol MgO * 40.3 g/mol = 100.75 grams MgO.
How many grams of iodine are produced when 0.72 mol of fluorine reacts with potassium iodide KI 2 KI F2 -- 2 KF I2?
From the balanced chemical equation, 2 moles of potassium iodide (KI) react with 1 mole of fluorine (F2) to produce 2 moles of iodine (I2). Therefore, when 0.72 mol of fluorine reacts, it produces 0.72 mol/2 = 0.36 mol of iodine. To convert this to grams, you would multiply the moles by the molar mass of iodine (I2), which is approximately 253.8 g/mol. So, 0.36 mol * 253.8 g/mol ≈ 91.4 grams of iodine are produced.
