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Because it takes 2a to make 1mol of a2b, the ratio is 1mol a2b/2mol a. If you only have 1.0 mol of a to react, then 1mol a x (1mol a2b/2 mol a)= 0.5 mol of a2b Because it takes 1 mol of b to make 1 mole of a2b, the ratio is 1mol a2b/1mol b. So, 1.0 mol b x (1mol a2b/1mol b)= 1.0 mol of a2b. Since you run out of a to react with b, a is the limiting reagent meaning that you can only produce 0.5 mol of a2b even though you have an excess amount of b. So, only 0.5 mol of a2b can be produced.
m= 0.977g Find the formula weight- Cd= 112.411amu S=32.065amu so CdS = 144.476amu or units in (g/mol) so multiply 6.76e-3 (mol) * 144.476 (g/mol) = 0.977g
10500
It depends on the substance and its molar mass.In order to convert from grams to formula units, you must first convert grams to moles, then moles to formula units (grams --> moles --> formula units).1. Divide the mass (g) of the given substance by the substance's molar mass.2. Multiply the number of moles found in Step 1 (above) by Avogadro's number (6.022 x 1023).---- Mass substance ----- X 6.022 x 1023 formula unitsMolar mass substanceCONVERSION FACTOR47.63g substance x 1 mol substance ---- x ----- Avogadro's number///////////////////// molar mass (g) substance ////// 1 mol substance
CaC12
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
To determine how many moles of aluminum are produced from 33 grams, divide the given mass by the molar mass of aluminum, which is approximately 26.98 g/mol. So, 33 g / 26.98 g/mol ≈ 1.22 moles of aluminum are produced.
110 g ammonia are produced.
89,6 g ammonia are obtained.
4.33 mol of N2 will produce twice as many moles of NH3 since the balanced chemical equation is N2 + 3H2 -> 2NH3. Therefore, 4.33 mol of N2 will produce 8.66 mol of NH3. To convert this to grams, use the molar mass of NH3 (17.03 g/mol) to find that 8.66 mol is equal to 147.43 grams of NH3.
The molar mass of Hg is 200.59 g/mol and of O is 16.00 g/mol. HgO consists of 1 Hg and 1 O atom, so the molar mass of HgO is 200.59 + 16.00 = 216.59 g/mol. To find the mass of mercury produced, we calculate the molar mass ratio of Hg to HgO: (200.59 g/mol Hg) / (216.59 g/mol HgO) = 0.926. When 16 grams of HgO are heated, the mass of mercury produced would be 16 g * 0.926 ≈ 14.82 grams.
Using the balanced chemical equation: 2Mg + O2 -> 2MgO, we can see that 1 mol of O2 reacts with 2 moles of Mg to produce 2 moles of MgO. Calculate the moles of O2: 40g O2 / 32g/mol = 1.25 mol O2 From the equation, 1.25 mol O2 will produce 2.5 mol of MgO. Calculate the grams of MgO produced: 2.5 mol MgO * 40.3 g/mol = 100.75 grams MgO.
From the balanced chemical equation, 2 moles of potassium iodide (KI) react with 1 mole of fluorine (F2) to produce 2 moles of iodine (I2). Therefore, when 0.72 mol of fluorine reacts, it produces 0.72 mol/2 = 0.36 mol of iodine. To convert this to grams, you would multiply the moles by the molar mass of iodine (I2), which is approximately 253.8 g/mol. So, 0.36 mol * 253.8 g/mol ≈ 91.4 grams of iodine are produced.
The balanced chemical equation for the reaction is: N2 + 3H2 -> 2NH3 From the equation, it can be seen that 1 mol of N2 produces 2 mol of NH3. Therefore, 3.38 mol of N2 will produce 2 x 3.38 = 6.76 mol of NH3. To convert this to grams, you need to multiply the molar mass of NH3 (17.03 g/mol) by the number of moles of NH3 produced. Thus, 6.76 mol of NH3 will produce 6.76 x 17.03 = 115.18 g of NH3.
The answer is 0,3422 grams.
92.4 grams