It depends how much the raw ingredients weighed at the start of the experiment !
The reactants are the substances that are doing the reacting to produce the result. (The substances on the left side of the equation are the reactants) So ZnS & O2 are the reactants.
2ZnO
The balanced equation for the reaction between zinc (Zn) and oxygen (O2) is: 2Zn + O2 -> 2ZnO
To balance the chemical equation ZnS + O2 = ZnO + SO2, you need to make sure that the number of each type of atom is the same on both sides of the equation. Start by adding coefficients to the compounds; in this case, a coefficient of 2 in front of ZnS and SO2 balances the equation: 2 ZnS + 3 O2 = 2 ZnO + 2 SO2.
Sulfur dioxide has the chemical formulaSO2Each sulfur atom (S) unites with one oxygen molecule (O2)Thus, S +O2 ---> SO2
Zinc reacts with oxygen to form zinc oxide. The chemical equation is: 2Zn + O2 → 2ZnO.
The compound made from the elements Zinc and oxygen is zinc oxide. The chemical equation is 2Zn + O2 = 2ZnO .
When zinc burns in oxygen, it forms zinc oxide. This reaction is exothermic and produces heat and light. The chemical equation for this reaction is: 2Zn + O2 → 2ZnO.
Zn+ H2O ---> ZnO + H2 Zn+ H2O ---> ZnO + H2
The equation that you need is 2ZnS + 3O2 ======> 2ZnO + 2SO2The equation is a 2 to 3 molar. The coefficients in the equation tell you how many moles of each reactant you need. So as the equation is 2ZnS + 3O2 that means 2 moles of ZnS is needed to react with 3 moles of O2. Since the question gives you 1.72 moles of ZnS and 3.04 moles of O2 the ZnS will run out first as 1.72 divided by 2 is 0.86 and 3.04 divided by 3 is 1.0133333... therefore we have less ZnS
2ZnS + 3O2 ---> 2ZnO + 2SO2 Zinc sulphide + Oxygen ---> Zinc oxide + Sulphur dioxide This reaction is endothermic and requires a heat change (H) in order to happen. As the Zinc sulphide reacts with the oxygen the zinc becomes oxidised (oxidation, zinc atoms bond to oxygen atoms), and during this reaction sulphur dioxide is given off.
Zinc+oxygen----> zincoxide