The reactants are the substances that are doing the reacting to produce the result. (The substances on the left side of the equation are the reactants)
So ZnS & O2 are the reactants.
2ZnS + 3O2 = 2ZnO + 2SO2
It depends how much the raw ingredients weighed at the start of the experiment !
Sulfur dioxide has the chemical formulaSO2Each sulfur atom (S) unites with one oxygen molecule (O2)Thus, S +O2 ---> SO2
The equation that you need is 2ZnS + 3O2 ======> 2ZnO + 2SO2The equation is a 2 to 3 molar. The coefficients in the equation tell you how many moles of each reactant you need. So as the equation is 2ZnS + 3O2 that means 2 moles of ZnS is needed to react with 3 moles of O2. Since the question gives you 1.72 moles of ZnS and 3.04 moles of O2 the ZnS will run out first as 1.72 divided by 2 is 0.86 and 3.04 divided by 3 is 1.0133333... therefore we have less ZnS
2ZnS + 3O2 ---> 2ZnO + 2SO2 Zinc sulphide + Oxygen ---> Zinc oxide + Sulphur dioxide This reaction is endothermic and requires a heat change (H) in order to happen. As the Zinc sulphide reacts with the oxygen the zinc becomes oxidised (oxidation, zinc atoms bond to oxygen atoms), and during this reaction sulphur dioxide is given off.