There are 424 grams of oxygen in 477 grams of water. 8 times 53 equals 424.
25.78g
if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
1.296 grams = 0.001296kg
2068 grams
16 grams of oxygen how many moles is 0,5 moles.
The answer is 224,141 grams oxygen.
There are 192 grams of oxygen in 6 moles of O2.
320 grams of oxygen is the equivalent of 10 moles.
There are 424 grams of oxygen in 477 grams of water. 8 times 53 equals 424.
12.8 grams oxygen (1 mole O/16.0 grams) = 0.800 moles of oxygen
1,9 grams
There are three oxygen atoms in 3.45 grams of water (H2O).
We need 14,8 g oxygen.
There are 0.47 grams of oxygen in 0.53 grams of NaHCO3.
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.