0
Assuming that each person makes a shaking partnership just once and no one shakes there own hand,Consider the situation. The eight people are in a line. The first person goes down the line shaking hands with everyone else so he shakes hands 7 times. He then sits down.
The second person shakes hands with everyone left in line, six handshakes, and sits down, He has no need to shake ands with the sitting man as they already shook.
The remainder follow the same procedure, shaking hands with those standing, not shaking with those sitting.
The last man standing shakes with no one as no one is standing and sitsThe sum of hand shakings initiated by each person is 7+6+5+4+3+2+1+0 = 28
Still curious? Ask our experts.
Chat with our AI personalities
Jordan
Lao
RossAdd your answer:
Earn +20 pts
How many people were at a party if There were 105 handshakes at a party and if each person at the party shook hands with exactly once with every other person.?
15 (15 * 15 - 15)/2 = 105
If every person at a party shakes the hand of every other person and there were 105 handshakes in all How many persons were present at the party?
The answer is 15 people. Each shook hands with 14 others, and there are half that many handshakes (pairs). The total number of pairs (distinct handshakes) within the group is defined by the formula T = [n!/(n-2)!] /2 Given T = 105 we get n!/(n-2)!=210 which implies n(n-1)=210 on solving we get n=15
10 people met at a party Each person shook every other hand once How many handshakes occurred?
9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 55
How many people at a party if 28 hand shakes were done and everyone only did one handshake?
28 people each shook hands once...?
Which is correct--- they shook hands or they shaked hands?
"They shook hands" is correct.
