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On a farm there are three-legged-cows and horses There are total of 59 heads and 211 legs How many three-legged-cows are on the farm?
If all animals were horses there would be 4 x 59 ie 236 legs. There is a shortage of 25 legs so there are 25 cows (and 34 horses).
On a farm there are three-legged-cows and horses There are total of 96 heads and 313 legs How many three-legged-cows are on the farm?
There are 96 heads, so 96 animals. If all were horses, that would be 4 x 96 = 384 legs, but there are only 313 legs, which means there are 384-313 = 71 legs short or 71 cows and 25 horses. Mathematically, let x = horses and y = cows x + y = 96 4x + 3y = 313 multiply first equation by 4: 4x + 4y = 384 4x + 3y = 313 subtract equations y = 71 = cows x = 25 = horses
There are some children and dogs on the beach Together they have 25 heads and 64 legs How many dogs How many children?
This is very easy. You just need to draw 25 heads, give each head 2 legs and then add 2 legs to as many as possible until you run out of legs. The answers; There are 7 dogs and 18 children.
On a farm there are chickens and horses there are a total of 66 heads and 182 legs how many chickens are on the farm?
We know that chickens have two legs, horses have four legs, and that both of them have one head each. With that, and the given numbers, we can say: c + h = 66 ∴ h = 66 - c 2c + 4h = 182 ∴ 2c + 4(66 - c) = 182 ∴ 2c + 264 - 4c = 182 ∴ -2c = -82 ∴ c = 41 So we know that there are 41 chickens. We can then plug that number into either of our given equations to find out how many horses we have: c + h = 66 ∴ 41 + h = 66 ∴ h = 25 Or: 2c + 4h = 182 ∴c + 2h = 91 ∴ 41 + 2h = 91 ∴ 2h = 50 ∴ h = 25
On a farm there are three-legged-cows and chickens there are a total of 119 heads and 332 legs how many three-legged-cows are on the farm?
94 three legged cows and 25 chickens.
