If all animals were horses there would be 4 x 59 ie 236 legs. There is a shortage of 25 legs so there are 25 cows (and 34 horses).
There are 96 heads, so 96 animals. If all were horses, that would be 4 x 96 = 384 legs, but there are only 313 legs, which means there are 384-313 = 71 legs short or 71 cows and 25 horses. Mathematically, let x = horses and y = cows x + y = 96 4x + 3y = 313 multiply first equation by 4: 4x + 4y = 384 4x + 3y = 313 subtract equations y = 71 = cows x = 25 = horses
This is very easy. You just need to draw 25 heads, give each head 2 legs and then add 2 legs to as many as possible until you run out of legs. The answers; There are 7 dogs and 18 children.
We know that chickens have two legs, horses have four legs, and that both of them have one head each. With that, and the given numbers, we can say: c + h = 66 ∴ h = 66 - c 2c + 4h = 182 ∴ 2c + 4(66 - c) = 182 ∴ 2c + 264 - 4c = 182 ∴ -2c = -82 ∴ c = 41 So we know that there are 41 chickens. We can then plug that number into either of our given equations to find out how many horses we have: c + h = 66 ∴ 41 + h = 66 ∴ h = 25 Or: 2c + 4h = 182 ∴c + 2h = 91 ∴ 41 + 2h = 91 ∴ 2h = 50 ∴ h = 25
94 three legged cows and 25 chickens.
If all animals were horses there would be 4 x 59 ie 236 legs. There is a shortage of 25 legs so there are 25 cows (and 34 horses).
If all were horses there would be 4 x 61 ie 244 legs. There is a shortfall of 50 legs ie 25 less four-legged creatures, so there are 36 horses and 25 chickens, giving 144 + 50 legs
There are 96 heads, so 96 animals. If all were horses, that would be 4 x 96 = 384 legs, but there are only 313 legs, which means there are 384-313 = 71 legs short or 71 cows and 25 horses. Mathematically, let x = horses and y = cows x + y = 96 4x + 3y = 313 multiply first equation by 4: 4x + 4y = 384 4x + 3y = 313 subtract equations y = 71 = cows x = 25 = horses
This is very easy. You just need to draw 25 heads, give each head 2 legs and then add 2 legs to as many as possible until you run out of legs. The answers; There are 7 dogs and 18 children.
* 12531 legs * You only have two legs, assuming "you" are human or bird.
200 Legs.
We know that chickens have two legs, horses have four legs, and that both of them have one head each. With that, and the given numbers, we can say: c + h = 66 ∴ h = 66 - c 2c + 4h = 182 ∴ 2c + 4(66 - c) = 182 ∴ 2c + 264 - 4c = 182 ∴ -2c = -82 ∴ c = 41 So we know that there are 41 chickens. We can then plug that number into either of our given equations to find out how many horses we have: c + h = 66 ∴ 41 + h = 66 ∴ h = 25 Or: 2c + 4h = 182 ∴c + 2h = 91 ∴ 41 + 2h = 91 ∴ 2h = 50 ∴ h = 25
0 snakes do not have legs.
94 three legged cows and 25 chickens.
Do-it-in-your-head method: If all animals were chickens there would be 90 legs. There are 20 extra legs, each on a cow, so there are 20 cows and therefore 25 chickens.
Two ways to think about it: 1: 25% both heads 50% one of each 25% both tails -or- 2: 25% heads/heads 25% heads/tails 25% tails/heads 25% tails/tails
100