Heat of vaporization of water is 2.26 x 106 joules per kg. Therefore 1 gram of water will need 2.26 x 103 joules.
It depends on 1 gram of what.
1 gram = 1,000 milligrams
1 gram = 100 centigrams
1000 milligrams in 1 gram
Approximately 50,000 joules are released when 1 gram of LPG (liquefied petroleum gas) is burned.
There are approximately 17 kilojoules in 1 gram of protein.
It takes 4.184 joules of energy to change the temperature of 1 gram of water by 1 degree Celsius.
There are approximately 9 calories, or 37.7 kilojoules, in 1 gram of fat.
Roughly 4.18400 joules Raising 1 gram of water 1 degree c requires 1 calorie (the definition of calorie includes the actual starting temperature, I think something like 3 degrees celsius). 1 calorie = 4.18400 joules
The latent heat of fusion for H2O ice to water is 334 joules/gram. This means that 334 joules of energy are required to convert 1 gram of ice at 0°C into 1 gram of water at 0°C. This process occurs at a constant temperature and does not result in a change in temperature.
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
The latent heat of fusion of water at atmospheric pressure is 334 joules per gram. This means that it takes 334 joules of energy to change 1 gram of ice at 0°C to 1 gram of water at 0°C.
The mechanical equivalent of heat is 4.2 Joules per calorie, so 4.2 Joules can heat 1 gram of water by 1 degree C.
The process that requires water to gain 2260 joules of energy per gram is known as specific heat capacity. Water has a specific heat capacity of 4.18 J/g°C, which means it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
It depends on the temperature of the water. 1 calorie equals roughly 4.184 joules, and 1 calorie equals roughly 1 degree C in a gram of water. (the actual definition includes a specific temperature, I think about 3 degrees C). So you could say that 1 gram of water contains roughly 4.18400 joules per degree above absolute zero, so 1 gram of near-freezing water is about 273 degrees * 4.184 joules/degree = about 1142 joules.
It takes 333.51 or 334 joules to evaporate 1 gram of H2O.