Considering it is kw for kilowatt and not kv.
1 megawatt = 1000 kilowatt.
50
The dielectric field strength of air is 4 to 30 kV/cm. So a voltage of less than 4 kV is not enough to cause a spark to jump a 1 cm air gap. A voltage over 30 kV is plenty to cause a spark to jump a 1 cm air gap. Within that range, pointy conductors allow a spark to form at lower voltage than smoothly rounded conductors. Different gases and gas pressures also have an effect on the exact voltage required to produce a spark.
2feet
it all depends on what electric motor,nitro or gas engine you have and the size and mixture of nitro you have (if your using a nitro engine), and for the electric motors it depends on what size motor and how many kv it has and what size and type of battery your using.
Amio khujchi
3 Kv = 3,000 volts.
A voltage of 13.8 kV is equal to 13,800 volts.
There are 0.001 KV in one V.
2,100 volts = 2.1 kv
There are 20,000 volts in 20 kV (kilovolts).
You cannot convert Volts (or kv, 1000 volts) to watts (or mega watts, 1,000,000 watts) because volts are measure of electric potential difference between two points and watts are a measure of energy/time. However, WATTS = VOLTS x AMPS so... if you have 1000 AMPS flowing over a resistance/load with a difference in potential of 1000 volts (1 KV), you have 1,000,000 WATTS (1 MEGAWATTS) of energy consumed/time. So if a motor has 1KV potential accross its terminals and it is consuming 1,000 AMPS, it is a 1 MegaWatt motor (a large one indeed). To get energy, you have to multiply this 1MegaWatt x the time the motor runs and x a conversion factor to get to the appropriate unit of energy. Yes, I've been called a nerd before.
The number of amps in 1 MVA (megavolt-ampere) will depend on the voltage of the system. To calculate amperes, you can use the formula: Amperes = MVA / (sqrt(3) x kV), where kV is the voltage of the system in kilovolts.
13,800 volts 1 kv = 1 kilovolt = 1000 volts
There is no city KV. KV stands for Kilo Volts
Multiples of 11 kV are used in many countries. The idea is to deliver a round number of volts so you add on 10% to allow for line losses. So 10 kV becomes 11 kV. In practice lines are operated without a 10% voltage drop now because it represents an unacceptable waste of energy, but we have stuck with 11 kV etc. Common supply voltages used for area distribution are 6.6 kV, 11 kV, 33 kV, 66 kV and 132 kV.
The k in kV stands for 1,000 and the v stands for volts. Divide 25,000 by 1,000 you get 25 kv.
4160 volts