Vf = V0 + at --> 0 = (8.5 m/s) - (5.3 m/s²)t -> t = (8.5 m/s)/(5.3 m/s²) = 1.60377 s
a = m/s/s a = 560/1/7 a = 80m/s/s
Acceleration is measured in distance per unit timer per unit time, or in SI units this is usually m/s/s or m/s^2. If an object's velocity increases by 15 m/s in five seconds this is an average acceleration of: 15 m/s / 5 s = 3 m/s/s
m/s * .001 km/m * 3600 s/hr = m/s * 3.6 km.s/m.hr the conversion factor is therefore 3.6
f a river current is 8.0 m/s, and a boat is traveling 10.0 m/s upstream, what is the boat's speed relative to the riverbank?
Vf = V0 + at --> 0 = (8.5 m/s) - (5.3 m/s²)t -> t = (8.5 m/s)/(5.3 m/s²) = 1.60377 s
No. m per s is speed. Multiply it by a mass, such as kg, and you have momentum.
138 peanut per 12.6 oz +/-3%
26 cm/s=what m/min
299792500 m/s (about 300 million meters per second)
a = m/s/s a = 560/1/7 a = 80m/s/s
Change in velocity: (28 m/s) - (5 m/s) = 23 m/s Change in velocity divided by acceleration: (23 m/s) / (4.5 m/s2) = 5.111 seconds.
m/s or m/sec
well its 10 mm per cm so ur answer is: 0.032 m or 3.s cm
Acceleration is measured in distance per unit timer per unit time, or in SI units this is usually m/s/s or m/s^2. If an object's velocity increases by 15 m/s in five seconds this is an average acceleration of: 15 m/s / 5 s = 3 m/s/s
m/s * .001 km/m * 3600 s/hr = m/s * 3.6 km.s/m.hr the conversion factor is therefore 3.6
f a river current is 8.0 m/s, and a boat is traveling 10.0 m/s upstream, what is the boat's speed relative to the riverbank?