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∙ 13y agoVf = V0 + at --> 0 = (8.5 m/s) - (5.3 m/s²)t -> t = (8.5 m/s)/(5.3 m/s²) = 1.60377 s
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∙ 13y agoSo it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
The acceleration of a pendulum is zero at the lowest point of its swing.
A 1-dimensional interval (a, b) is continuous if for any k in (0, 1) the point a + k*(b-a) = a*(1-k) + k*b is also in the interval. This is equivalent to the statement that every point on the line joining a and b is in the interval. The above can be extended to more dimensions analogously.
An arc, which is a uniformly curved line with a common radii point.
Ratio
So it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
The car's average acceleration can be calculated using the formula: average acceleration = (final velocity - initial velocity) / time interval. Plugging in the values: (9.0 m/s - 9.5 m/s) / 3.5 s = -0.5 m/s^2. Therefore, the car's average acceleration in this time interval is -0.5 m/s^2.
Uniformly accelerated motion describes an object moving with a constant acceleration. This means the object's velocity changes by the same amount in each time interval. The equations of motion for uniformly accelerated motion can be used to predict the object's position, velocity, and acceleration at any point in time.
The velocity-time graph for a car first accelerating and then decelerating uniformly would have a positive slope during acceleration, representing an increase in velocity, and then a negative slope during deceleration, showing a decrease in velocity. The graph would form a "V" shape with two straight lines meeting at a point where the acceleration changes to deceleration.
Average acceleration is the change in velocity over a specific time interval, while instantaneous acceleration is the acceleration at a specific moment in time. Average acceleration gives an overall picture of how velocity changes over time, while instantaneous acceleration gives the acceleration at a precise point in time.
Interval estimates are generally to be preferred over point estimate
An open interval centered about the point estimate, .
Angular acceleration is got by the expression alpha = {(final angular velocity)2 - (initial ang velocity)2} / 2 theta. final is 50 and initial is 100 rad/s. Theta is 50 x 2pi radian Therefore required alpha = -50 x 150/200 pi = -75/2pi radian/s2 Negative sign indicates that the rotation is decelrated.
Instantaneous acceleration is the rate of change of velocity of an object at a specific moment in time. It provides information about how quickly the velocity of an object is changing at that exact instant. It is a vector quantity, meaning it has both magnitude and direction.
loads are carried out as point load uniformly distributed load and uniformly varying load
No, the acceleration at the highest point is never 0.
The acceleration of a pendulum is zero at the lowest point of its swing.