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How many kilocalories per kg per hour would expend exercising at 6 METS?

The answer to this can only be approximated. To do it, you need to know the oxygen consumption at 6 METS. The standard assumption for this is that 1 MET is 3.5 ml/min/kg of body weight. Now you need to know how many Calories are burned for each ml/min of VO2. This again, is only an approximation, because the answer depends on assumptions about muscle efficiency and fuel burned. When the RQ (ratio of VCO2/VO2) is about 0.8, we burn about 4.8 Cal per liter of VO2 (source: ACSM resource manual). So, here we go: 6 METS = 6 x 3.5 = 21 ml/min/kg of VO2. Assume a 70-kg body weight, this gives VO2 of 1.47 l/min. Now multiply by the KCal factor to get 7 Cal per minute, or 420 Cal per hour. Putting the answer in units per Kg as requested, gives 420/70 = 6 Cal/kg/hour. 6 METS is about 3.5 MPH at 5% grade (brisk walk up slight hill). Ken Beck Exercise Physiologist, and Research Scientist, Boston Scientific Corp


What did 50-4 40 or fight mean?

The phrase "50-4 40 or fight" is a slogan associated with the baseball team New York Mets, originating from a rallying cry by fans in the 1980s. It represents a desire for the team to achieve a winning record, specifically 50 wins and 40 losses, and reflects the passionate support of the fanbase. The phrase emphasizes a no-nonsense attitude towards performance, advocating for either success or a challenge.


What does a MET represent what does it measure?

A MET, or Metabolic Equivalent of Task, is a unit that measures the energy cost of physical activities as a multiple of resting metabolic rate. Specifically, 1 MET is defined as the energy expended while at rest, which is approximately 3.5 milliliters of oxygen consumed per kilogram of body weight per minute. MET values help quantify the intensity of various physical activities, allowing individuals to compare the energy expenditure of different exercises. For example, a task that requires 8 METs would use eight times the energy expended at rest.