Depends on the bowl size.
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The best way would be to use the ancient Archemedean way: take a bowl or similar object that can fully contain the rock in question. Put the bowl in a large pan. Fill the bowl completely with water, all the way up to the very rim. Now, submerge the rock completely in the bowl, so that it is entirely underwater. Water will spilled out of the bowl into the pan. Remove the bowl from the pan, and pour the water from the pan into a measuring cup - the volume of that water is the volume of the rock.
pour water into it until full, then pour that water into a measuring cup.
As the bowl is hemispherical in share, tilting it does not change the shape of the water, and so its depth remains the same. When the bowl has been tilted 35o, the distance the lip of the bowl has been lowered can be found using the Sine ratio. This can be subtracted from the height the lip was above the bottom the the bowl (namely the radius of the bowl) to find how deep the water is. The angle is 35o. The hypotenuse is the radius of the bowl. The opposite side is the unknown drop. sine 35o = drop/20 cm ⇒ drop = 20cm x sine 35o ≈ 11.47 cm height = radius - drop ≈ 20 cm - 11.47 cm = 8.53 cm
The word 'pour' has one syllable.
Fill it up with water, dry the shell off and pour the water into some sort of measuring device? Or.. Since water weighs about 1kg/liter you could pour water into the shell and then weigh the water to know the volume..