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The best way would be to use the ancient Archemedean way: take a bowl or similar object that can fully contain the rock in question. Put the bowl in a large pan. Fill the bowl completely with water, all the way up to the very rim. Now, submerge the rock completely in the bowl, so that it is entirely underwater. Water will spilled out of the bowl into the pan. Remove the bowl from the pan, and pour the water from the pan into a measuring cup - the volume of that water is the volume of the rock.
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How can you figure out the density of a irregular rock?
To determine the density of an irregular rock, you can use the water displacement method. First, measure the initial volume of water in a graduated cylinder. Then, submerge the rock completely in the water and measure the new water level; the difference in volume indicates the rock's volume. Finally, divide the mass of the rock (measured using a scale) by the volume obtained from the water displacement to calculate the density.
How could you figure out the volume of an irregular solid such as a rock?
Fill a bowl of water that is bigger than the rock right to the top, add the rock, collect and measure the volume of how much water is spilt. Provide the rock is not porous or very soluble this will provide the volume of the rock.
How do you find the volume of n irregularly shaped rock?
use a graduated cylinder or other volume measuring container. just put a certain amount of water in, take note of it, then put the rock in and measure the difference, make sure the water goes up and above the rock though
How can the volume of a irregularly shaped rock be measured?
One way would be to get a container into which you could put the rock completely, fill it to the brim with water (without the rock in it), then put the rock in and measure the volume of the water that flowed out.
What unit of measure would you use to measure the amount of matter in an object?
You would use Volume.
