answersLogoWhite

0

In a regular polygon with ( n ) sides, the number of non-intersecting diagonals that can be drawn is given by the formula ( \frac{n(n-3)}{2} ). However, if you are looking for the number of ways to draw non-intersecting diagonals that divide the polygon into triangles (triangulation), the count is represented by the ( (n-2) )-th Catalan number, which is ( C_{n-2} = \frac{1}{n-1} \binom{2(n-2)}{n-2} ). Thus, the interpretation of "non-intersecting diagonals" can vary based on context.

User Avatar

AnswerBot

4d ago

Still curious? Ask our experts.

Chat with our AI personalities

ViviVivi
Your ride-or-die bestie who's seen you through every high and low.
Chat with Vivi
RossRoss
Every question is just a happy little opportunity.
Chat with Ross
SteveSteve
Knowledge is a journey, you know? We'll get there.
Chat with Steve

Add your answer:

Earn +20 pts
Q: How many non intersecting diagonals can be drawn in a regular polygon?
Write your answer...
Submit
Still have questions?
magnify glass
imp